It is impossible but if it were x squared plus 2x minus 15 the equation would be (x+5) (x-3) with x being equal to either -5 or 3. If the original problem was x squared minus 2x minus 15 the equation would be (x-5)(x+3) and x would be equal to either 5 or -3
x2 - 3x - 40 = (x - 8) (x + 5)
(X-5)(X+4)=0 so X-5=0 -----X=5 and X=4=0 so X=-4 it factors to (X-5)(X+4) so X=5,-4
(x + 2)(x - 4)
x2 - 5x = 0Factor the left side:x (x - 5) = 0x = 0x = 5
(x - 5)(x + 4)
(x−6)(x+5)
x squared plus 5
It is: (x+5)(x-8) when factored
It is: (x+5)(x-8) when factored
(x - 5)(x + 3)
2
No
It is impossible but if it were x squared plus 2x minus 15 the equation would be (x+5) (x-3) with x being equal to either -5 or 3. If the original problem was x squared minus 2x minus 15 the equation would be (x-5)(x+3) and x would be equal to either 5 or -3
(x - 5)(x^2 + 1)
x - 3
x - 5