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Earn +20 ptsQ: How do you factor x squared minus 3x minus 40?
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6x squared minus 58x plus 80 equals 0?
6x2 + 58x + 80 = 02(40 + 29x + 3x2) = 02((8 + x)(5 + 3x)) = 0, ignore 28 + x = 0 => x = -85 + 3x = 0 => 3x = 5 => x= 1.666666....x = {-8, 1.66....}
How do you solve 8-3x equals 128?
8-3x = 128 -3x = 128-8 -3x = 120 x = -40
IF 7x -4 equals 3x plus 36 what is x?
7x-4 = 3x+36Add 4, it cancels out.. So,7x = 3x+40Now subtract 3x from 7x..4x = 40..40 divided by 4 is 10So, X= 10
What is the sum of three consecutive integers is -123?
Algebraically. X = integer. X + (X + 1) + (X + 2) = - 123 3X + 3 = - 123 3X = - 126 X = - 42 X + 1 = - 41 X + 2 = - 40 - 42 + - 42 + - 40 = -123 =======
What are the values of x in this quadratic equation 2x squared-x-5 equals 0?
2x2 - x - 5 = 0 x = [1 +/- sqrt(1 + 40)]/4 = [1 +/- sqrt(41)]/4 = -1.35078 and 1.85078
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