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6x squared minus 58x plus 80 equals 0?
6x2 + 58x + 80 = 02(40 + 29x + 3x2) = 02((8 + x)(5 + 3x)) = 0, ignore 28 + x = 0 => x = -85 + 3x = 0 => 3x = 5 => x= 1.666666....x = {-8, 1.66....}
How do you solve 8-3x equals 128?
8-3x = 128 -3x = 128-8 -3x = 120 x = -40
IF 7x -4 equals 3x plus 36 what is x?
7x-4 = 3x+36Add 4, it cancels out.. So,7x = 3x+40Now subtract 3x from 7x..4x = 40..40 divided by 4 is 10So, X= 10
What is the sum of three consecutive integers is -123?
Algebraically. X = integer. X + (X + 1) + (X + 2) = - 123 3X + 3 = - 123 3X = - 126 X = - 42 X + 1 = - 41 X + 2 = - 40 - 42 + - 42 + - 40 = -123 =======
What are the values of x in this quadratic equation 2x squared-x-5 equals 0?
2x2 - x - 5 = 0 x = [1 +/- sqrt(1 + 40)]/4 = [1 +/- sqrt(41)]/4 = -1.35078 and 1.85078
What is the factorization of 24x squared minus 49x minus 40?
(3x - 8)(8x + 5)
What is x squared minus 3x minus 40?
It is: (x+5)(x-8) when factored
How do you simplify 3x squared plus 7x minus 40 divided by x plus 5?
Factorise it: (x + 5)(3x - 8)
How do you factor negative two x squared minus 22x plus 40?
Factor out -2: -2(x squared +11x-20). This is fully factored.
What is the solution to this equation 4x plus 10 plus 3x equals 40 minus 3x?
4x + 10 + 3x = 40 - 3x 4x + 10 + 3x + 3x = 40 20x = 40 x = 2
Factor x2 plus 3x - 40?
x2 + 3x - 40 = (x + 8)(x - 5)
What is x squared minus x minus 40?
It is: (x+5)(x-8) when factored
4x squared plus 12x minus 40 divided by x minus 2?
4x + 20
What is 40 minus 2 times 3 squared?
40 - 2*32 = 40-2*9 = 40 - 18 = 22
6x squared minus 58x plus 80 equals 0?
6x2 + 58x + 80 = 02(40 + 29x + 3x2) = 02((8 + x)(5 + 3x)) = 0, ignore 28 + x = 0 => x = -85 + 3x = 0 => 3x = 5 => x= 1.666666....x = {-8, 1.66....}
Factor 4x squared - 16x plus 40?
No solution in integers.
Factor x2 plus 3x-40?
x2 + 3x - 40 = x2 + 8x - 5x - 40 = x(x + 8) - 5(x + 8) = (x - 5)(x + 8)
