It is: (x+5)(x-8) when factored
Factorise it: (x + 5)(3x - 8)
(x+4)(x-7)
3x2-x-2 = (3x+2)(x-1)
x³ + x² - 3x - 3 = (x + 1)(x + √3) (x - √3).
3x2 - 8x = x(3x - 8)
x2 - 3x - 40 = (x - 8) (x + 5)
Factorise it: (x + 5)(3x - 8)
x^2 + 3x + 2/(-3x) - x^2 - 2=3x-2+2/(-3x)=3x-2-2/(3x)
(x+4)(x-7)
x(3x - 2)
(x-3)(3x+1)
3x2-x-2 = (3x+2)(x-1)
(3x + 1)(x - 5)
(3x^(2) - 6x) / 3x Factor the numerator Hence 3x(x -2) / 3x Cancel down by '3x' Hence x -2 is the answer.
3x^(2) +9x - 2x -6 Collect 'like terms'. Hence 3x^(2) + 7x - 6 Next write down all the factors of '3' and '6' Hence 3 ; 1' & 3' 6 ; 1,6 ; 2,3. From these pairs of number we select a pair from each coefficient, that add/multiply to '7' . Hence (3' x 3 ) & (1' x 2) ; NB 'dashes' (') to indicate source of numbers. Write up brackets (3x 2)(x 3) -2)(x + 3) Next we notice that the '6' is negative, so the two signs are different (+/-) The '7x' is positive , so the larger number takes the positive sign . Hence (3x - 2)(x + 3)
What is the question? Do you want to factor 3x2 -x -2? If that is the question the answer is (3x + 2)(x-1)
x³ + x² - 3x - 3 = (x + 1)(x + √3) (x - √3).