Factorise it: (x + 5)(3x - 8)
(x+4)(x-7)
3x2-x-2 = (3x+2)(x-1)
(x + 3)(3x - 2)
3x2 - 8x = x(3x - 8)
x2 - 3x - 40 = (x - 8) (x + 5)
Factorise it: (x + 5)(3x - 8)
x^2 + 3x + 2/(-3x) - x^2 - 2=3x-2+2/(-3x)=3x-2-2/(3x)
(x+4)(x-7)
x(3x - 2)
(x-3)(3x+1)
3x2-x-2 = (3x+2)(x-1)
(3x + 1)(x - 5)
(3x2 - 6x)/3x = 3x(x-2)/3x = x-2, for x<>0
(x + 3)(3x - 2)
What is the question? Do you want to factor 3x2 -x -2? If that is the question the answer is (3x + 2)(x-1)
3x2 - 8x = x(3x - 8)