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Q: What is x to the fifth power divided by x to the negative 3 power?

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Fifth degree - the highest power of x that appears.

y / 3

2.3333

24\3=8

I will assume that this is sopposed to be integrated with respect to x. To make this problem easier, imagine that the integrand is x raised to the negative 3. The integral is 1/(-2x-2) plus some constant c.

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Negative one fifth (-1/5) divided by negative 3 is positive one fifteenth (1/15)

Three divided by three to the negative 4th power is 243.

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3 times 10 to the 8th power divided by 7 times 10 to the negative 7th power equates to: 4.28571428571

That's the same as 1 divided by (x to the power 3).

1

(6x^5 + 12x) / (-2x^-3) =[ (6x^5 + 12x) (x^3) ] / (-2) =(6x^8 + 12x^4) / (-2)=(3x^8 + 6x^4) =(3x^4)[ (x^4) + 2 ]

It is: (8*10^-3) divided by (5*10^-5) = 160

one fifth divided by one third is 3 fifths

0.3333

negative 9 divided by negative 3 is 3 andnegative 3 minus 1 is negative 2

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