Another contributor's answer:
This appears to be a quadratic equation question in form of:
2x2-x-6 = 0
When factorised:
(2x+3)(x-2) = 0
Therefore: x = -3/2 or x = 2
2x2+1x-3=0 4+x-3=0 x+1+0 x=-1 is your final answer
2x2-7x+3 = 0 (2x-1)(x-3) = 0 x = 1/2 or x = 3
The product of the roots of the equation 2x2 -x -2 = 2 is 2x2 -x -2 = 2.
Differentiate the function with respect to x: d/dx (x3 - 2x2 - 5x + 6) = 3x2 - 4x - 5 Set this derivative = 0 and solve. 3x2 - 4x - 5 = 0 implies that x = -0.7863 or 2.1196 (to 4 dp)
2x2 + 7x - 15 = 02x2 + 10x - 3x - 15 = 0(2x2 - 3x) + (10x - 15) = 0x(2x - 3) + 5(2x - 3) = 0(2x - 3)(x + 5) = 0(2x - 3) = 0 or (x + 5) = 0x = 3/2 or x = -5
2x2 = 10x + 12 2x2 - 10x - 12 = 0 x2 -5x -6 = 0 x2 - 6x + x - 6 = 0 x(x -6) + 1(x -6) = 0 (x+1)(x-6) = 0 x = -1 or x = 6
x2+7x=-2x2+6 3x2+7x-6=0 (3x-2)(x+3)=0 3x-2=0 or x+3=0 x=2/3 or x=-3
2x2-x-3 = 0= 4 - x - 3 = 0= 1 - x = 0= 1 = xTherefore x = 1
The answer is x=0
This is a quadratic equation question which will have two answers: 2x2+42 = x2+13x 2x2-x2-13x+42 = 0 x2-13x+42 = 0 Factorising the equation gives you: (x-6)(x-7) = 0 Therefore: x = 6 or x = 7
2x2+18x = 20 2x2+18x-20 = 0 x2+9x-10 = 0 (x+10)(x-1) = 0 x = -10 or x = 1
8 - 2x2 = x + 22 - 7Combine like terms on the right side:8 - 2x2 = x + 15Subtract 8 from each side:-2x2 = x + 7Add 2x2 to each side:0 = 2x2 + x + 7
I'm assuming the question is: 2x2 = 24x x = 0 or x = 12
2x2 + 7x = 0 => x(2x+7)=0 so x = 0 or 2x+7 = 0 ie x = 0 or x = -7/2
2x2+1x-3=0 4+x-3=0 x+1+0 x=-1 is your final answer
If: 2x2-3x+1 = 0 Then: x = 1 or x = 1/2
2x2-7x+3 = 0 (2x-1)(x-3) = 0 x = 1/2 or x = 3