Another contributor's answer:
This appears to be a quadratic equation question in form of:
2x2-x-6 = 0
When factorised:
(2x+3)(x-2) = 0
Therefore: x = -3/2 or x = 2
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2x2+1x-3=0 4+x-3=0 x+1+0 x=-1 is your final answer
2x2-7x+3 = 0 (2x-1)(x-3) = 0 x = 1/2 or x = 3
The product of the roots of the equation 2x2 -x -2 = 2 is 2x2 -x -2 = 2.
Differentiate the function with respect to x: d/dx (x3 - 2x2 - 5x + 6) = 3x2 - 4x - 5 Set this derivative = 0 and solve. 3x2 - 4x - 5 = 0 implies that x = -0.7863 or 2.1196 (to 4 dp)
2x2 + 7x - 15 = 02x2 + 10x - 3x - 15 = 0(2x2 - 3x) + (10x - 15) = 0x(2x - 3) + 5(2x - 3) = 0(2x - 3)(x + 5) = 0(2x - 3) = 0 or (x + 5) = 0x = 3/2 or x = -5