2x2 + 7x = 0 => x(2x+7)=0
so x = 0 or 2x+7 = 0
ie x = 0 or x = -7/2
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x2 + 7x = 2x2 + 6 x2 - 2x2 + 7x = 6 -x2 +7x - 6 = 0 or alternatively x2 - 7x + 6 = 0
(2x + 1)(x + 3) = 0; x = -0.5 or -3
2x2 + 7x + 3 = (2x + 1)(x + 3)If 2x2 + 7x + 3 = 0 then:(2x + 1)(x + 3) = 0⇒ (2x + 1) = 0 → x = -1/2or (x + 3) = 0 → x = - 3
x = -1.5 or -2 2x2 + 7x + 6 = 0 => (2x + 3)(x + 2) = 0 Thus 2x + 3 = 0 => x = -1.5 or x + 2 = 0 => x = -2
-7