Oh, dude, you're hitting me with some math lingo! So, when you say y 3, you're talking about y cubed. And when you say y3y3-y, you're basically asking for y cubed times y cubed minus y. So, technically, the answer is y to the 6th power minus y. Math can be fun, right?
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Let y = 3x y' = 3(x)' y' = 3(x1)' y' = 3[1x(1-1)] y' = 3(1x0) y' = 3(1 x 1) y' = 3 In general: y = xn y' nx(n-1)
y(y-3)(y+3)
y=2x-3 y=-x-3
7x + y + 3 = y7x + 3 = 07x = -3x = -3/7