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6
Let y = 3x y' = 3(x)' y' = 3(x1)' y' = 3[1x(1-1)] y' = 3(1x0) y' = 3(1 x 1) y' = 3 In general: y = xn y' nx(n-1)
y(y-3)(y+3)
y / 3
y=2x-3 y=-x-3
Y^3(Y^3-Y)=???We know Y=3 so this, Y^3(Y^3-Y) now looks like this..3^3(3^3-3)For the outsidewe know 3^3=27Ex. 3x3x3=27Break Down3x3=9x3=27So from Y^3(Y^3-Y)we went to 3^3(3^3-3)to this 27(27-3)Now subtract 27-3=24to get you final X27(24)= or 27*24= 648Steps...Y^3(Y^3-Y)Y^3(Y^3-Y)3^3(3^3-3)27(27-3)27(24)= or 27*24= 648
When y itself is negative, -y becomes positive.Suppose y is -3.Then -y is -(-3) which is +3. Got it? Hope so.When y itself is negative, -y becomes positive.Suppose y is -3.Then -y is -(-3) which is +3. Got it? Hope so.When y itself is negative, -y becomes positive.Suppose y is -3.Then -y is -(-3) which is +3. Got it? Hope so.When y itself is negative, -y becomes positive.Suppose y is -3.Then -y is -(-3) which is +3. Got it? Hope so.
3+y=y+3 -3 -3 y=y any number
You cannot. y-3 + y-3 + y-3 +y-3 = 4y-12 is an expression, not an equation. An expression cannot be solved since there is nothing to solve.
y=3 y^3(y^3-y)= 3^3(3^3-3)= 27(27-3)= 27(24)=648
x - y = -3 -y = -x - 3 y = x + 3 y-int. = 3 x-int. = -3
y = 9 -------- y = -2x + 3 x = -3 y = (-2)(-3) + 3 y = 6 + 3 y = 9
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If y = 2x+3 then the y intercept at is 3 on the y axis but if y = 2x-3 then the y intercept is at -3 on the y axis
y-2x=3 -y -y -2x=3-y -3 -3 -2x-3=-y /-1 /-1 2x+3=y y=2x and y=2x+3 have the same slope of 2, so they are parallel. Hope this helps! ;D
y = 3 (y^3)(y^3 - 1) = (3^3)(3^3 - 1) = 27(27 - 1) = 27(26) = 702
Let y = 3x y' = 3(x)' y' = 3(x1)' y' = 3[1x(1-1)] y' = 3(1x0) y' = 3(1 x 1) y' = 3 In general: y = xn y' nx(n-1)