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Let

y = 3x

y' = 3(x)'

y' = 3(x1)'

y' = 3[1x(1-1)]

y' = 3(1x0)

y' = 3(1 x 1)

y' = 3

In general:

y = xn

y' nx(n-1)

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โˆ™ 2009-08-05 23:29:18
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Q: What is the derivative of 3x?
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