Let
y = 3x
y' = 3(x)'
y' = 3(x1)'
y' = 3[1x(1-1)]
y' = 3(1x0)
y' = 3(1 x 1)
y' = 3
In general:
y = xn
y' nx(n-1)
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The derivate of 3x is 3; the derivative of -1 is 0. So, the derivative of 3x-1 is simply 3.The derivate of 3x is 3; the derivative of -1 is 0. So, the derivative of 3x-1 is simply 3.The derivate of 3x is 3; the derivative of -1 is 0. So, the derivative of 3x-1 is simply 3.The derivate of 3x is 3; the derivative of -1 is 0. So, the derivative of 3x-1 is simply 3.
If y = 3x +- 1, the derivative with respect to x is y' = 3.
3e3x
3sec2(3x)
the derivative of 3x is 3 the derivative of x cubed is 3 times x squared