y(y-3)(y+3)
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y^(2) + 9y - 52 # Write down all the factors of '52' Hence 1, 52 ; 2 , 26 ; 4 , 13 ; By addition or subtraction, select a pair of factors that 'add' to '9' They are, '4' & '13' ; Hence 13 - 4 = 9 Set up ther brackets , without the signs Hence ( y 4)(y 13) Since '52' is negative (-) , then the two signs are different. Since '9' is positive then the larger factor is positive(+). Hence inserting (y - 4)(y + 13) Factored!!!! Done!!!!
Oh, dude, you're hitting me with some math lingo! So, when you say y 3, you're talking about y cubed. And when you say y3y3-y, you're basically asking for y cubed times y cubed minus y. So, technically, the answer is y to the 6th power minus y. Math can be fun, right?
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3x - 9y = 27-9y = -3x + 279y = 3x - 27y = x/3 - 3The graph is a straight line, with (slope = 3), and passing through the point (y = - 3) on the y-axis.
9x2 - 6xy + y2 - 81 = (3x - y)2 - 81 = (3x - y - 9)*(3x - y + 9)