T = 3x + 7y; x = 4; y = 6
T = 3x + 7y (substitute 4 for x, and 6 for y)
T = 3(4) + 7(6) = 12 + 42 = 54
10y = 9y + 4, so y = 4
9x-9y = 36 => x-y = 4 3(-y+x = 4) 7y-3x = -14 Multiply all terms in the top equation by 3: -3y+3x = 12 7y-3x = -14 Add both equations together: 4y = -2 Divide both sides by 4: y = -0.5 Substitute the value of y into the original equations to find the value of x: x = 3.5 and y = -0.5
3x+4=10 To solve: 3x+4=10 3x=6 x=2
7x = 3 x = 3/7
3x-4=5x+6 gives: 2x=-10 which gives x=-5
4
3x + 7y = 3*x + 7*y = 3*6 + 7*4 = 18 + 28 = 46
x+7y=16 ---------------------------1 3x- 7y=4 ---------------------------2 ------------------------------------------------------------------------------------------------------------------ 1+2 x+7y=16 3x-7y=4 4x=20 x=5 substitute x = 5 in x+7y=16 (5)+7y=16 7y=11 y=11/7
y = -1 and x = -3
The ordered pair is (5, 4).
If you mean: x+7y = 39 and 3x-2y = 2 Then by substitution: x = 4 and y = 5
x = 5 and y = 4
12y - 4 = 7y + 165y = 20y = 4
If: 3x-7y+4 = 0 then 3x-7y = -4 The intercepts are at: x is at (-4/3, 0) and y is at (0, 4/7) Distance of x from the origin: 4/3 Distance of y from the origin: 4/7 Area of the triangle: 1/2*4/3*4/7 = 8/21 square units
4(1-4x+7y)
Their graphs are.
(2, -1)