In mathematics, when we have an equation with two variables like y = f(x), we can find the value of y when x is three by substituting x = 3 into the equation. Without the specific equation provided, it is impossible to determine the value of y when x is three. The solution would depend on the function or relationship between y and x given in the equation.
Assuming that the equation is y = 3x + 2, y decreases by three times as much as the decrease in x.
Both. If you look at it like this: y=41-x you say x is independent and y is dependent of x (i.e. y is a function of x) For x=41-y you say y is independent and x is dependent of y (i.e. x is a function of y)
The answer to Y x plus 5 Y 6 is Y(x+5Y5).One possible solution to y x plus 5 y 6 is Y(x+5Y5).
-6
This question makes no sense! Which are the x-values, and which are the y-values?
If y varies directly as x and y is 18 when x is 24, then y is always three fourths of x. So if y is 15, then x is 20.
y = 3 + (-x) or y = 3 - x
No. It can be written in three ways: x/y x:y or x to y.
8
y is directly proportional to x. When y = 15, x = 3 therefore y = 5x When x = 12, then y = 5 x 12 = 60.
To find two times the sum of ( x^2 ) and ( y^2 ) increased by three times the sum of ( x^2 ) and ( y^2 ), we first express it mathematically. The sum of ( x^2 ) and ( y^2 ) is ( x^2 + y^2 ). Thus, two times this sum is ( 2(x^2 + y^2) ), and three times it is ( 3(x^2 + y^2) ). Adding these together gives ( 2(x^2 + y^2) + 3(x^2 + y^2) = 5(x^2 + y^2) ).
3tx and y
(x+y)/2
The expression "x negative 6 divided by y three" can be interpreted as ((x - 6) / (y + 3)). This means you subtract 6 from x and then divide that result by the sum of y and 3. If you need a numerical solution, you would need specific values for x and y.
x is 987 subtract y is 123 ,which 987-123=864.
If ( x^3 = Y ), you can solve for ( x ) by taking the cube root of both sides. Thus, ( x = \sqrt[3]{Y} ). This means that ( x ) is the value that, when raised to the power of three, equals ( Y ).
x=4, y=3