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∫ cot(x) dx is written as:

∫ cos(x) / sin(x) dx

Let u = sin(x). Then, du = cos(x) dx, giving us:

∫ 1/u du

So the integral of 1/u is ln|u|. So the answer is ln|sin(x)| + c

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11y ago
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Q: What the integral of cotx?
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