∫ cot(x) dx is written as:
∫ cos(x) / sin(x) dx
Let u = sin(x). Then, du = cos(x) dx, giving us:
∫ 1/u du
So the integral of 1/u is ln|u|. So the answer is ln|sin(x)| + c
Chat with our AI personalities
- ln (cscx + cotx) + C You use u substitution.
The integral of cot (x) dx is ln (absolute value (sin (x))) + C. Without using the absolute value, you can use the square root of the square, i.e. ln (square root (sin2x)) + C
8
Do you mean the Convolution Integral?
The integral of -x2 is -1/3 x3 .