y = (sinx)^(e^x)
ln(y) = ln((sinx)^(e^x))
ln(y) = (e^x)ln(sinx)
(1/y)dy = (e^x)(1/sinx)(cosx)+ln(sinx)(e^x)dx
(1/y)dy = (e^x)(cotx)+ln(sinx)(e^x)dx
dy = ((sinx)^(e^x))((cotx)(e^x)+ln(sinx)(e^x))dx
dy = ((e^x)(sinx)^(e^x))(cotx+ln(sinx))dx
y"+y'=0 is a differential equation and mean the first derivative plus the second derivative =0.Look at e-x the first derivative is -e-xThe second derivative will be e-xThe sum will be 0
-e^(-x) or negative e to the negative x this is because you multiply the function (e) by: 1 / (the derivative of the power ... in this case: -1) e^(-x) * (1/-1) = -e^(-x) Don't forget to add your constant!
(eu)'=ueu-1
If dy/dx = (e) (9x) then Y = 4.5ex2 plus (any constant).==================================The above answer explains how to get the integral of e9x.If you were interested in how to get the derivative of e9x, the answer is e9.I suspect you may have actually wanted to ask how to get the derivative of e9x.In that case, the derivative of e9x is 9e9x.
d/dx e3x = 3e3x
The first derivative of e to the x power is e to the power of x.
The derivative of ex is ex
e^(-2x) * -2 The derivative of e^F(x) is e^F(x) times the derivative of F(x)
I assume you mean 27 times e to the power x. 1) You take out the constant out. So, the derivative is 27 times the derivative of (e to the power x).2) You use the rule for the exponential function.
d/dx (e-x) = -e-x
e^[ln(x^2)]=x^2, so your question is really, "What is the derivative of x^2," to which the answer is 2x.
The anti-derivative of sqrt(x) : sqrt(x)=x^(1/2) The anti-derivative is x^(1/2+1) /(1/2+1) = (2/3) x^(3/2) The anti-derivative is 4e^x is 4 e^x ( I hope you meant e to the power x) The anti-derivative of -sin(x) is cos(x) Adding, the anti-derivative is (2/3) x^(3/2) + 4 e^x + cos(x) + C
e^[ln(x^2)]=x^2, so your question is really, "What is the derivative of x^2," to which the answer is 2x.
y = e^ln x using the fact that e to the ln x is just x, and the derivative of x is 1: y = x y' = 1
Your expression simplifies to just x^2 {with the restriction that x > 0}. The derivative of x^2 is 2*x
ee is a constant and so its derivative is 0.
d/dx (ex + x3) = ex + 3x2