2x + 3y = 12
5y = x + 7
Express both equations as functions of x, that is the form y = ..., and find the intersection point.
y = (-2/3)x + 4
y = x/5 + 7/5
(-2/3)x + 4 = x/5 + 7/5
(-2/3)x - x/5 = 7/5 - 4 multiply both sides by the common denominator, 15
-10x - 3x = 21 - 60
- 13x = -39 divide by -13 to both sides
x = 3
To find the value of y, substitute 3 for x in one of the given equations.
y = (-2/3)x + 4
y = (-2/3)(3) + 4
y = -2 + 4
y = 2
Thus, the intersection point (3,2) satisfies both equations, and this point lies on both lines.
Check:
answer is 1
There are no common points for the following two equations: y = 2x + 3 y = 2x - 1 If you graph the two lines, since they have the same slope, they are parallel - they will never cross.
x + 20 + 10x = 20 + 9x 11x + 20 = 20 + 9x Subtract 20 from both sides: 11x = 9x Subtract 9x from both sides: 2x = 0 Divide both sides by 2: x = 0
The lines are perpendicular, and intersect at the point (1.35, 3.55) .
There are infinitely many answers and they comprise the coordinates of all points on the line that satisfy the equation.
No because the slope in both lines have different values
Yes, they're parallel lines. Both slopes are 2.
The slope is ' 5 ', so both lines MUST be parallel.
The slope of both lines is 8. So they're parallel.
They are parallel lines.
They are straight lines.
They are parallel lines.
The lines are mutually perpendicular.
That system of equations has no solution. When the two equations are graphed, they turn out to be the same straight line, so there's no such thing as a single point where the two lines intersect. There are an infinite number of points that satisfy both equations.
parallel
The lines are parallel, but not the same.
Perpendiculat straight lines.