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Why tan x graph is continuous within its domain and is not continuous out of the domain?
we do not check if a function is continuous or not outside it's domain.
"first, f has to be defined at c."
Tanx is not defined where cosx=0 .ie x=pi/2 , 3pi/2 etc
ill try to help more here.
what domain means is what can you put into a function, whereas range, which i am sure you have heard of as well, just means what you can get out of a function. that being said, lets look further into the graph of tanx. when we do, we see that the graph is discontinuous at pi/2. the reason for this is because tanx is equivalent to sinx/cosx. because of this relationship, when you put pi/2 in for x in sinx/cosx, you end up with cosx=0 which makes your denominator zero, which is undefined, which makes your graph discontinuous. because of that, you cannot put pi/2 in for x in tanx, and since the domain is what you can put into an equation, pi/2 which causes a discontinuity is not included in the domain. basicly, wherever a graph is discontinuous, it wont be included in the domain because you cant put stuff in that will make your graph discontinuous
What else can I help you with?
When you are given a graph how can you come up with a rational function equation?
You cannot, necessarily. Given a graph of the tan function, you could not.
Which expression has the same value as tan(-x) for all values for x?
tan(-x) = -tan(x)
Sec x times sin x divided by tan x?
1 (sec x)(sin x /tan x = (1/cos x)(sin x)/tan x = (sin x/cos x)/tan x) = tan x/tan x = 1
Sin x Tan x equals Sin x?
No. Tan(x)=Sin(x)/Cos(x) Sin(x)Tan(x)=Sin2(x)/Cos(x) Cos(x)Tan(x)=Sin(x)
How do you prove tan x plus tan x sec 2x equals tan 2x?
tan x + (tan x)(sec 2x) = tan 2x work dependently on the left sidetan x + (tan x)(sec 2x); factor out tan x= tan x(1 + sec 2x); sec 2x = 1/cos 2x= tan x(1 + 1/cos 2x); LCD = cos 2x= tan x[cos 2x + 1)/cos 2x]; tan x = sin x/cos x and cos 2x = 1 - 2 sin2 x= (sin x/cos x)[(1 - 2sin2 x + 1)/cos 2x]= (sin x/cos x)[2(1 - sin2 x)/cos 2x]; 1 - sin2 x = cos2 x= (sin x/cos x)[2cos2 x)/cos 2x]; simplify cos x= (2sin x cos x)/cos 2x; 2 sinx cos x = sin 2x= sin 2x/cos 2x= tan 2x
What is a function whose graph has one or more breaks?
The tan [tangent] function.When a function has two or more brakes, this is not a continuous function, but it can be a continuous function in some intervals such as the tangent does.
When you are given a graph how can you come up with a rational function equation?
You cannot, necessarily. Given a graph of the tan function, you could not.
Why is the arctangent function restricted to the first and fourth quadrants?
A function cannot be one to many. Suppose y = tan(x) Now, since tan(x) = tan(x + pi) then tan(x + pi) = y But that means arctan(y) can be x or x+pi In order to prevent that sort of indeterminacy, the arctan function must be restricted to an interval of width pi. Any interval of that width would do and it could have been restricted to the first and second quadrants, or even from -pi/4 to 3*pi/4. The problem there is that in the middle of that interval the tan function becomes infinite which means that arctan would have a discontinuity in the middle of its domain. A better option, then, is to restrict it to the first and fourth quarters. Then the asymptotic values occur at the ends of the domain, which leaves the function continuous within the whole of the open interval.
Is there a graph of y equals equals 2 tan 2x?
Yes, that is a shifted tanX graph, just as you would shift any graft.
How do you graph cool images on a ti 84?
This is for a cool bridge. First, press the (Y=) button. Then, follow the orders of these buttons: (MATH), (Right Arrow), (Enter), (TAN), (TAN), (COS), the X variable button, (Right Arrow), (*), (-), (1), and then press graph
What describes the domain of y tan x where n is any integer?
x=pi/2+npi
How do you graph a line using polar coordinates?
This only works for y=mx, not y=mx+c. theta = tan(m) eg y=x theta = tan(1) .: theta = 45
What is the angle between a line of a graph and a positive direction of the x-axis?
The angle is the arc-tan of the gradient of the line. That is to say, the tangent of that angle is the gradient of the line or the angle between the straight line and the positive x-axis. Arc tan may also be written as tan-1 but that is frequently confused with 1/tan or the cotangent function.
What is a black-and-tan?
A black-and-tan is any of a group of dog breeds with black and tan colouring, or a historical term for a bar or nightclub within the United States which admitted both black and white members.
What is black and tan?
A black-and-tan is any of a group of Dog Breeds with black and tan colouring, or a historical term for a bar or nightclub within the United States which admitted both black and white members.
Are black and tan Jack Russells normal?
Yes, black and tan Jack Russells are a recognized color variation within the breed. While the more common color combination is white with black or tan markings, black and tan Jack Russells can still be purebred and are considered normal within the breed standard.
What is ratio of the tension of the band block breaks?
Band and block brakes: Sometimes instead of applying continuous friction lining along the band, blocks of wood or other frictional materials are inserted between the band and the drum. In this case the tensions within the band at both sides of a block bear the relation T1/T1'= (1+mue Tan (theta))/(1-mue Tan(theta))
