A function cannot be one to many.
Suppose y = tan(x)
Now, since tan(x) = tan(x + pi)
then tan(x + pi) = y
But that means arctan(y) can be x or x+pi
In order to prevent that sort of indeterminacy, the arctan function must be restricted to an interval of width pi.
Any interval of that width would do and it could have been restricted to the first and second quadrants, or even from -pi/4 to 3*pi/4. The problem there is that in the middle of that interval the tan function becomes infinite which means that arctan would have a discontinuity in the middle of its domain. A better option, then, is to restrict it to the first and fourth quarters. Then the asymptotic values occur at the ends of the domain, which leaves the function continuous within the whole of the open interval.
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A point with a zero abscissa (x-coordinate) and a negative ordinate (y-coordinate) would lie in the fourth quadrant of the Cartesian coordinate system. In this quadrant, the x-coordinate is positive or zero, while the y-coordinate is negative. This means that the point would be to the right of the y-axis (positive x-direction) and below the x-axis (negative y-direction).
Circles that lie completely within the fourth quadrant of the Cartesian plane have their centers in the fourth quadrant and have a radius smaller than the distance from the center to the x-axis and y-axis. In other words, the circle's center coordinates (x, y) must both be positive, and the radius r must be less than both x and y. This ensures that the entire circle falls within the boundaries of the fourth quadrant.
You need to clarify the function AND provide an interval.
The word for three quarters of a circle is "quadrant." A quadrant is a sector equal to one fourth of a circle, so three quadrants make up three quarters of a circle. Each quadrant measures 90 degrees, totaling 270 degrees for three quarters of a circle.
fourth