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128 equals x to the power 7 what is x how do i use logarithms to solve it?
128 = x7 (we see that x > 0, since x is raised to an odd power) 27 = x7 (this is true only when x = 2) 2 = x Remember that a logarithm is an exponent. The statement 128 = x7 is equivalent to logx 128 = 7. logx 128 = 7 log 128/log x = 7 (or reverse the both sides) log x/log 128 = 1/7 (multiply by log 128 to both sides) log x = log128/7 (or use base 10 for the logarithm) log10 x = log128/7 (write the equivalent statement) 10log 128/7 = x 2 = x or use the natural log, ln. 128 = x7 ln 128 = ln x7 ln 128 = 7ln x (ln 128)/7 = ln x e(ln128)/7 = elnx (elnx = x ) 2 = x
How does f(x)7x change over the interval from x5 to x7?
If the x value changes u, then the y value changes by 7u.
What is 23 is what percent of 46?
46 is the 23% of 200.23 x = 4623 x = 4600x = 200
X2 - 4x - 29 equals -10?
Assuming that by expressing that equation as a question you're looking to solve for x: x2 - 4x - 29 = -10 x2 - 4x + 4 = 23 (x - 2)2 = 23 x - 2 = ± √23 x = 2 ± √23
What is the vertex of y equals x2-x-23?
25
