128 = x7 (we see that x > 0, since x is raised to an odd power) 27 = x7 (this is true only when x = 2) 2 = x Remember that a logarithm is an exponent. The statement 128 = x7 is equivalent to logx 128 = 7. logx 128 = 7 log 128/log x = 7 (or reverse the both sides) log x/log 128 = 1/7 (multiply by log 128 to both sides) log x = log128/7 (or use base 10 for the logarithm) log10 x = log128/7 (write the equivalent statement) 10log 128/7 = x 2 = x or use the natural log, ln. 128 = x7 ln 128 = ln x7 ln 128 = 7ln x (ln 128)/7 = ln x e(ln128)/7 = elnx (elnx = x ) 2 = x
If the x value changes u, then the y value changes by 7u.
46 is the 23% of 200.23 x = 4623 x = 4600x = 200
Assuming that by expressing that equation as a question you're looking to solve for x: x2 - 4x - 29 = -10 x2 - 4x + 4 = 23 (x - 2)2 = 23 x - 2 = ± √23 x = 2 ± √23
25
sqrt(x7) = sqrt(x6*x) = x3*sqrt(x)or, more simply,sqrt(x7) = x7/2 = x3.5sqrt(x7) = sqrt(x6*x) = x3*sqrt(x)or, more simply,sqrt(x7) = x7/2 = x3.5sqrt(x7) = sqrt(x6*x) = x3*sqrt(x)or, more simply,sqrt(x7) = x7/2 = x3.5sqrt(x7) = sqrt(x6*x) = x3*sqrt(x)or, more simply,sqrt(x7) = x7/2 = x3.5
Depends on where the parentheses are. X(7-4) + X7 + 4 = 10X + 4 X(7-4) + X(7+4) = 14X
x7
(x4 * x10)/(x7)x14/x714 - 7 = 7= x7===
x7 is the same as 7x. However, x^7 is significantly different from 7x
In mathematics, the symbol "x" typically represents multiplication. Therefore, "x7" means multiplying a number by 7. For example, if you have the expression 5 x 7, it would equal 35.
It is 1 in 7.
There is a formula for the "difference of squares." In this case, the answer is (x7 - 7)(x7 + 7)
It is: 4 x 7 = 28
x = 9
16 x 9 x 5 x 7 = 5040
1400=23 x 52 x7