x = 3y - 3 so 6 (3y - 3) + 2y = -12 ie 18y - 18 + 2y = -12
ie 20y = 6 so y = 0.3 and x = -2.1
3y - 3 = 2y + 5 3y - 2y = 5 + 3 y = 8
x=4 y=0
Solving for y: 5y = 9 + 2y 5y - 2y = 9 3y = 9 y = 9/3 = 3
5 - 2y = -3y - 2Subtract 5 from each side:-2y = -3y - 7Add 3y to each side:y = -7
The lines are perpendicular, and intersect at the point (1.35, 3.55) .
If 3y = 12, 2y = 8
5y = 3y + 12 5y - 3y = (3y - 3y) + 12 2y = 12 y = 6
3y - 3 = 2y + 5 3y - 2y = 5 + 3 y = 8
perpendicular
5y-2y= 3y+2 5y-2y-3y= 2 0y= 2
2y + 3 = 3y + 9 2y - 3y = 9 - 3 or -y = 6 so y = -6
2y=8..... y=4
x = 3 and y = 2
2y+3y-7y+4=16 -2y=12y=-6Check it-12-18+42+4=16-30+46=1616=16
9y-3y=6y; 6y+2y=8y; so your answer is 8y
Perpendiculat straight lines.
(x, y) = (3, 7) is a solution.