x = 3y - 3 so 6 (3y - 3) + 2y = -12 ie 18y - 18 + 2y = -12
ie 20y = 6 so y = 0.3 and x = -2.1
-3 + 3y = 2y + 5 Add '3' to both sides Hence 3y = 2y + 8 Subtract '2y' from both sides. y = 8 The answer!!!!!
Solving for y: 5y = 9 + 2y 5y - 2y = 9 3y = 9 y = 9/3 = 3
5 - 2y = -3y - 2Subtract 5 from each side:-2y = -3y - 7Add 3y to each side:y = -7
The lines are perpendicular, and intersect at the point (1.35, 3.55) .
First get y in terms of x: 5x-2y=-12 ----- -2y=-12-5x ------ y=6+(5/2)x Sub into other equation: 2x+3y=-1 ---- 2x+3(6+(5/2)x)=-1 Solving for x gets: x= -2 Sub into other equation: 5x-2y= -12 --- 5(-2)-2y= -12 --- y=1 So x= -2, and y= 1
If 3y = 12, 2y = 8
5y = 3y + 12 5y - 3y = (3y - 3y) + 12 2y = 12 y = 6
perpendicular
5y-2y= 3y+2 5y-2y-3y= 2 0y= 2
2y + 3 = 3y + 9 2y - 3y = 9 - 3 or -y = 6 so y = -6
2y=8..... y=4
2y+3y-7y+4=16 -2y=12y=-6Check it-12-18+42+4=16-30+46=1616=16
x = 3 and y = 2
9y-3y=6y; 6y+2y=8y; so your answer is 8y
-3 + 3y = 2y + 5 Add '3' to both sides Hence 3y = 2y + 8 Subtract '2y' from both sides. y = 8 The answer!!!!!
Perpendiculat straight lines.
(x, y) = (3, 7) is a solution.