5y = 3y + 12 5y - 3y = (3y - 3y) + 12 2y = 12 y = 6
2y + 3 = 3y + 9 2y - 3y = 9 - 3 or -y = 6 so y = -6
2x+6y = 24 5x-2y = 9 Divide all terms in the top equation by 2: x+3y = 12 => x = 12-3y Substitute x = 12-3y into the bottom equation: 5(12-3y)-2y = 9 60-15y-2y = 9 -15y-2y = 9-60 -17y = -51 y = 3 Substitute the value of y into the original equations to find the value of x: Answer: x = 3 and y = 3
Plot the straight line representing 2y = 12 - x. Plot the straight line representing 3y = x - 2 The coordinates of the point of intersection of these two lines is the solution to the simultaneous equations.
5y + (4 - 2y) = 9 5y + 4 - 2y = 9 3y + 4 = 9 3y = 5 y = 5/3
2y=8..... y=4
5y = 3y + 12 5y - 3y = (3y - 3y) + 12 2y = 12 y = 6
x = 3y - 3 so 6 (3y - 3) + 2y = -12 ie 18y - 18 + 2y = -12 ie 20y = 6 so y = 0.3 and x = -2.1
For y - 2y - 3y equals 0, y equals 0.
5y-2y= 3y+2 5y-2y-3y= 2 0y= 2
5 - 2y = -3y - 2Subtract 5 from each side:-2y = -3y - 7Add 3y to each side:y = -7
perpendicular
3y - 3 = 2y + 5 3y - 2y = 5 + 3 y = 8
2x-3y=5 and x-2y=12x-3y+2y=5 and x-2y+2y=12x-y=5 and x=12(1)-y=52-y=52-y-2=5-2-y=3y=-3(x,y) is (1,-3)
9y-3y=6y; 6y+2y=8y; so your answer is 8y
2y+3y-7y+4=16 -2y=12y=-6Check it-12-18+42+4=16-30+46=1616=16
2y + 3 = 3y + 9 2y - 3y = 9 - 3 or -y = 6 so y = -6