Subtract first from second gives -4x = 16 so x = -4 and y = -7
2y+5y=10 7y=10 y=10/7
3x - 2y + 7x + 4y = 3x + 7x - 2y +4y = (3+7)x + (-2+4)y = 10x + 2y
3
5 - 2y = -3y - 2Subtract 5 from each side:-2y = -3y - 7Add 3y to each side:y = -7
x = 11/7 and y = 12/7
5y-7 = 2y+11 (+7 to both sides) 5y = 2y+18 (- 2y from both sides) 3y = 18 (divide both sides by 3 ) y = 6 y=6
The slope of the line of 2x plus 2y equals 7 is (7/2x - 1).
3x + 2y = 7
x+2y = 7 2y = -x+7 y = -0.5x+3.5
It is 2y + 22 = 2(y + 11)
If: 3x+2y = 5x+2y = 7 which is the same as 7 = 7 = 7 Then: 3x+2y = 7 and 5x+2y = 7 Subtracting equations: x = 0 Therefore by substitution: x = 0 and y = 3.5
3x-2y-7=0
3x = 2y + 7 The standard form is: 3x - 2y - 7 = 0
If: 3x+2y = 5x+2y = 7 Then: 3x+2y = 7 and 5x+2y = 7 Subtract the 1st equation from the 2nd equation: 2x = 0 or x = o By substitution: x = 0 and y = 3.5
7+2y=15subtract 7 from each side of the equal sign2y=8divide each side by 2y=4
2y-7 = 14y+29 2y = 14y + 36 -12y = 36 -y = 3 y = -3