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What is the line with slope -2 and y-intercept 8?
y=-2x+8
What are the solutions to the simultaneous equations of x -2y equals 1 and 3xy -y2 equals 8?
If: x-2y = 1 then x = 2y+1 If: 3xy -y^2 = 8 then 3*(2y+1)*y -y^2 = 8 So: 6y^2 +3y -y^2 = 8 or 5y^2 +3y -8 = 0 Factorizing the above: (y-1)(5y+8) = 0 meaning y = 1 or y = -8/5 Solutions by substitution are: (3, 1) and (-11/5, -8/5)
X plus y equals 10 y equals X plus 8 subsitute this method?
x + y = 10 y = x + 8 so, x + (x + 8) = 10 2x + 8 = 10 2x + 8 - 8 = 10 - 8 2x = 2 x = 1 and y = 9 because y = x + 8 y = 1 + 8 y = 9
What are the solutions to the simultaneous equations of 3xy -y squared equals 8 and x -2y equals 1?
The two equations are: 1) 3xy - y² = 8 2) x - 2y = 1 Make x the subject of (2): x - 2y = 1 → x = 2y + 1 substitute for x in (1) and solve for y: 3xy - y² = 8 → 3(2y + 1)y - y² = 8 → 6y + 3y - y² - 8 = 0 → 5y + 3y - 8 = 0 → (5y + 8)(y - 1) = 0 → 5y + 8 = 0 → y = -8/5 or y - 1 = 0 → y = 1 and substitute into 2 to find the corresponding x: y = -8/5 → x = 2(-8/5) + 1 = -11/5 y = 1 → x = 2(1) + 1 = 3 → the solutions are the ordered pairs (-11/5, -8/5) {or (-2.2, -1.6)} and (3, 1)
What is a solution to these equations X plus Y equals -8 and 2x - y equals 4?
x+y=-8 2x-y=4 y=-x-8 2x+x+8=4 3x=-4 x=-4/3 -4/3 + y= -8 y = -8 + 4/3 y= -6 2/3
