8(y - 1)(y^2 + y + 1)
8(y - 1)(y^2 + y + 1)
(2 - 3x)(9x^2 + 6x + 4)
All that is factorable here is the common factor t.t3 - 8tt(t2 - 8)======
64 x cubed minus y cubed is (4x - y)(16x^2 + 4xy + y^2)
9 minus 8
x cubed minus 216
t3-1/27
There are no factors with rational coefficients.
(c - z)(c^2 + cz + z^2)
000000
3x(x^2 - 5)
(a - 2)(a^2 + 6)