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CaSO4

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βˆ™ 11y ago
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βˆ™ 1mo ago

The empirical formula for this compound is CaSO4. This can be determined by converting the percentages to moles, finding the mole ratio, and simplifying the subscripts to the smallest whole number ratio.

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Q: What is the empirical formula for a compound that is 29.44 percent calcium 23.55 percent sulfur and 47.01 percent oxygen?
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Related questions

What is the empirical formula of a compound that contains 20 percent calcium and 80 percent bromine by mass?

The empirical formula would be CaBr2 since it contains a ratio of 1 calcium to 2 bromine atoms.


Empirical formula of a compound containing 60.3 percent magnesium and 39.7 percent oxygen?

The empirical formula of this compound would be MgO.


How do you know when to solve for a empirical formula?

You should solve for an empirical formula when you are given the percent composition of elements in a compound or when you have the molar mass of the compound but not the molecular formula. The empirical formula provides the simplest whole-number ratio of atoms in a compound.


Calculate the empirical formula of a compound formed from 3 percent C 0.3 percent H and 96.7 percent you Which formula below correctly represents the empirical formula?

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What is the percent composition of a compound with the empirical formula CO2?

The percent composition of a compound with the empirical formula CO2 is 27.3% carbon and 72.7% oxygen.


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What is the empirical formula for a compound that is 43.6 percent phosphorus and 56.4 percent oxygen?

p2o5


What is the empirical formula of a compound that is 40 percent sulfure and 60 percent oxygen?

The empirical formula of the compound with 40% sulfur and 60% oxygen is SO3 (sulfur trioxide). The ratio of sulfur to oxygen in the compound is 1:3, which simplifies to SO3.


What is the empirical formula for a compound that is 43.6 percent and 56.4 percent oxygen?

The empirical formula for the compound that is 43.6% carbon and 56.4% oxygen is CO2. This is because the ratio of carbon to oxygen in carbon dioxide is 1:2.


What is the empirical formula of a compound which is 64.80 percent carbon 6.35 percent hydrogen and 28.83 percent sulfur?

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What is the Empirical formula of the compound that is 52.7 percent K 47.3 percent Cl?

The empirical formula of the compound with 52.7% K and 47.3% Cl is KCl (potassium chloride). This is because the ratio of potassium to chlorine atoms in the compound is 1:1, leading to the simple formula KCl.


What is the empirical formula for 13 percent magnesium and 87 percent bromine?

The empirical formula for a compound containing 13% magnesium and 87% bromine is MgBr2. This is because the ratio of magnesium to bromine atoms in the compound is 1:2, which corresponds to the formula MgBr2.