CaSO4
The empirical formula of this compound would be MgO.
The percent composition of a compound with the empirical formula CO2 is 27.3% carbon and 72.7% oxygen.
The empirical formula of the compound with 40% sulfur and 60% oxygen is SO3 (sulfur trioxide). The ratio of sulfur to oxygen in the compound is 1:3, which simplifies to SO3.
The empirical formula for the compound that is 43.6% carbon and 56.4% oxygen is CO2. This is because the ratio of carbon to oxygen in carbon dioxide is 1:2.
The molar mass of the compound is 444.8 g/mol. To find the empirical formula, we need to determine the number of moles of each element in the compound. The molar ratio of thallium to oxygen is approximately 3:1, so the empirical formula is TlO3.
The empirical formula would be CaBr2 since it contains a ratio of 1 calcium to 2 bromine atoms.
The empirical formula of this compound would be MgO.
You should solve for an empirical formula when you are given the percent composition of elements in a compound or when you have the molar mass of the compound but not the molecular formula. The empirical formula provides the simplest whole-number ratio of atoms in a compound.
Chi a+
The percent composition of a compound with the empirical formula CO2 is 27.3% carbon and 72.7% oxygen.
CHI3
p2o5
The empirical formula of the compound with 40% sulfur and 60% oxygen is SO3 (sulfur trioxide). The ratio of sulfur to oxygen in the compound is 1:3, which simplifies to SO3.
The empirical formula for the compound that is 43.6% carbon and 56.4% oxygen is CO2. This is because the ratio of carbon to oxygen in carbon dioxide is 1:2.
C4h2s
The empirical formula of the compound with 52.7% K and 47.3% Cl is KCl (potassium chloride). This is because the ratio of potassium to chlorine atoms in the compound is 1:1, leading to the simple formula KCl.
The empirical formula for a compound containing 13% magnesium and 87% bromine is MgBr2. This is because the ratio of magnesium to bromine atoms in the compound is 1:2, which corresponds to the formula MgBr2.