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What is the empirical formula of a compound that contains 20 percent calcium and 80 percent bromine by mass?

The empirical formula would be CaBr2 since it contains a ratio of 1 calcium to 2 bromine atoms.


Empirical formula of a compound containing 60.3 percent magnesium and 39.7 percent oxygen?

The empirical formula of this compound would be MgO.


How do you know when to solve for a empirical formula?

You should solve for an empirical formula when you are given the percent composition of elements in a compound or when you have the molar mass of the compound but not the molecular formula. The empirical formula provides the simplest whole-number ratio of atoms in a compound.


Calculate the empirical formula of a compound formed from 3 percent C 0.3 percent H and 96.7 percent you Which formula below correctly represents the empirical formula?

Chi a+


What is the percent composition of a compound with the empirical formula CO2?

The percent composition of a compound with the empirical formula CO2 is 27.3% carbon and 72.7% oxygen.


Calculate the empirical formula of a compound formed from 3 percent c 3 percent h and 96 7 percent you which formula below correctly represents the empirical formula?

CHI3


What is the empirical formula for a compound that is 43.6 percent phosphorus and 56.4 percent oxygen?

p2o5


What is the empirical formula of a compound that is 40 percent sulfure and 60 percent oxygen?

The empirical formula of the compound with 40% sulfur and 60% oxygen is SO3 (sulfur trioxide). The ratio of sulfur to oxygen in the compound is 1:3, which simplifies to SO3.


What is the empirical formula for a compound that is 43.6 percent and 56.4 percent oxygen?

The empirical formula for the compound that is 43.6% carbon and 56.4% oxygen is CO2. This is because the ratio of carbon to oxygen in carbon dioxide is 1:2.


What is the empirical formula of a compound which is 64.80 percent carbon 6.35 percent hydrogen and 28.83 percent sulfur?

C4h2s


What is the Empirical formula of the compound that is 52.7 percent K 47.3 percent Cl?

The empirical formula of the compound with 52.7% K and 47.3% Cl is KCl (potassium chloride). This is because the ratio of potassium to chlorine atoms in the compound is 1:1, leading to the simple formula KCl.


What is the empirical formula for 13 percent magnesium and 87 percent bromine?

The empirical formula for a compound containing 13% magnesium and 87% bromine is MgBr2. This is because the ratio of magnesium to bromine atoms in the compound is 1:2, which corresponds to the formula MgBr2.