A 15,000-gallon pool has a volume of about 2,005 cubic feet.
A gallon of water occupies 231 cubic inches of space, as there are 231 cubic inches in a gallon. To find the area it fills in inches, we need to divide this volume by the height at which the water is spread. If we assume the water is spread evenly at a height of 1 inch, the area covered by a gallon of water would be 231 square inches.
75 x 30 x 5 = 11,250 cubic foot 1 cubic foot = 7.48 Gallon (US) 1 cubic foot = 6.23 Gallon (Imperial) 11,250 x 7.48 = 84,150 Gallon (US) 11,250 x 6.23 = 70,087.5 Gallon (Imperial)
there are 231 cubic inches in a gallon of water so there are 598.44 gallons of water in that size pool.
11*16*2.5 = 440 cubic feet. 440 cubic foot = 2 740.687 602 gallon [UK] 440 cubic foot = 3 291.428 571 4 gallon [US, liquid]
question is meaningless. gallon is a unit of volume, sq ft is a unit of area. the above is a horrible answer. simply put your question was miss worded. i believe you meant cubic foot (not square foot). the answer is 7.481 gallons in a cubic foot
One US Gallon has 231 cubic inches, and the area that you've given is 36 cubic inches. So, 36/231 gallons is the exact answer, which is approximately .1558 gallons (15.6% of 1 gallon)
350
(12 x 24 x 4) x (1,728 cubic inches per cubic foot) / (231 cubic inches per gallon) = 8,617.6 gallons
You will need about 463 cubic yards (around 594 tons) of gravel for this area.
Assuming the pool is rectangluar (and not an oval or some other shape), then the volume is 2,875,392 cubic inches. There are 231 cubic inches in a gallon, so the pool holds 12,447.58 gallons of water.
1 acre = 43,560 square feet1 cubic foot = 1,728 cubic inches1 gallon = 231 cubic inchesVolume of the lake = (1.5 x 43,560) x (5) = 326,700 cubic feet = 2,443,885.7 gallons (rounded)
A 15000 gallon pool could be about 25 FT. X 27 Ft. X 3 Ft. deep or a pool that has a diameter of 30 Ft. X 3 Ft. deep will hold 15,854 gallons of water.