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Alright this is not very well put, so I have three possible equations that I can think of on the fly. I will attempt to answer all three.

1) (4)5x-y=

+y +y

(4)5x=y

/4 /4

5x=y/4

/5 /5

[x=(y/4)/5]

2) (4x)5x-y=

20x2-y=

+y +y

20x2=y

/20 /20

[x2=y/20]

3) 4x=5x-y

+y +y

4x+y=5x

-4x -4x

[y=x]

1) (4)5x-y=

+y +y

[20x=y]

2) (4x)5x-y=

20x2-y=

+y +y

[20x2=y]

3) 4x=5x-y

+y +y

4x+y=5x

-4x -4x

[y=x]

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