Alright this is not very well put, so I have three possible equations that I can think of on the fly. I will attempt to answer all three.
1) (4)5x-y=
+y +y
(4)5x=y
/4 /4
5x=y/4
/5 /5
[x=(y/4)/5]
2) (4x)5x-y=
20x2-y=
+y +y
20x2=y
/20 /20
[x2=y/20]
3) 4x=5x-y
+y +y
4x+y=5x
-4x -4x
[y=x]
1) (4)5x-y=
+y +y
[20x=y]
2) (4x)5x-y=
20x2-y=
+y +y
[20x2=y]
3) 4x=5x-y
+y +y
4x+y=5x
-4x -4x
[y=x]
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