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B is (-5, 9).
Triangle B The area of a triangle is the length of the base times the height divided by two. Triangle A has base 13 m and height 5 m so we have (13 * 5) / 2 = 32.5 square meters. Triangle B has base 9 m and height 8 m so we have (9 * 8) /2 = 36 square meters. Therefore Triangle B has the greater area.
The equation for a straight line is y = mx+b whereas m is the slope and b is the y intercept For example: y = 3x+9 which means that 3 is the slope and 9 is the y intercept
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Slope intercept form is y = mx + b, with m as slope and b as y-intercept. In this case, m = 1 and b = -9. Slope = 1 (or 1.000 as a decimal)
y = mx + b m = (y2-y1)/(x2 - x1) = -9/8 using the first point: (x1 = -8, y1 = 0), then 0=-9 (-8/8) + b 0 = 9 + b, so b = -9. y = (-9/8) x - 9
To complete the square for a quadratic ax² + bx + c = 0 1) Divide through by the coefficient of the x² term to get x² + b/a x + c/a = 0; let B = b/a; let C = c/a; the equation is now x² + Bx + c = 0 2) Complete the square by taking half of B and adding it to x and squaring: (x + B/2)² 3) Expanding this gives: (x + B/2)² = x² + Bx + (B/2)² → x² + Bx = (x + B/2)² - (B/2)² 4) Substitute this in the original equation to give: x² + BX + C = (x + B/2)² - (B/2)² + C 5) This can now be solved as (x + B/2)² - (B/2)² + C = 0 → (x + B/2)² = (B/2)² - C For m² - 6m - 7 = 0, completing the square gives: (m - 6/2)² - (6/2)² - 7 = 0 → (m - 3)² - 9 - 7 = 0 → (m - 3)² -16 = 0 → (m - 3)² = 16 → m - 3 = ±4 → m = 3 ± 4 → m = 7 or -1.
-2X -3Y = 9 -3Y = 2X + 9 3Y = -2X -9 Y = -2/3X -3 This is standard form Y = mX + b where m = slope and b = y intercept since m = -2/3 any line with that slope is parallel. Y = -2/3X + b where b = ANY NUMBER
B x M = 2 * 7 - 8 +9 =16 _ __(YOUR ANSWER)