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Which triangle has the greater area triangle A has base 13 m and height 5 m and triangle B has base 9 m and height 8 m?
Triangle B The area of a triangle is the length of the base times the height divided by two. Triangle A has base 13 m and height 5 m so we have (13 * 5) / 2 = 32.5 square meters. Triangle B has base 9 m and height 8 m so we have (9 * 8) /2 = 36 square meters. Therefore Triangle B has the greater area.
What is the slope of the line given by the equation y equals x - 9 Enter your answer as a decimal?
Slope intercept form is y = mx + b, with m as slope and b as y-intercept. In this case, m = 1 and b = -9. Slope = 1 (or 1.000 as a decimal)
What is the root of the equation m squared -6m -7 equals 0 found by completing the square?
To complete the square for a quadratic ax² + bx + c = 0 1) Divide through by the coefficient of the x² term to get x² + b/a x + c/a = 0; let B = b/a; let C = c/a; the equation is now x² + Bx + c = 0 2) Complete the square by taking half of B and adding it to x and squaring: (x + B/2)² 3) Expanding this gives: (x + B/2)² = x² + Bx + (B/2)² → x² + Bx = (x + B/2)² - (B/2)² 4) Substitute this in the original equation to give: x² + BX + C = (x + B/2)² - (B/2)² + C 5) This can now be solved as (x + B/2)² - (B/2)² + C = 0 → (x + B/2)² = (B/2)² - C For m² - 6m - 7 = 0, completing the square gives: (m - 6/2)² - (6/2)² - 7 = 0 → (m - 3)² - 9 - 7 = 0 → (m - 3)² -16 = 0 → (m - 3)² = 16 → m - 3 = ±4 → m = 3 ± 4 → m = 7 or -1.
What is the sum of m a and m b?
ma + mb = m(a + b) this is an algebra formule, what cyfers, NUMBERS STAND A and M for I suspect that slashes representing fractions are missing: m/a + m/b = mb + ma/ab = m(b + a)/ab
What is the length of the base of a triangle with the height 9 m and area 18 m?
The formula for the area of a triangle is (1/2)bh. Filling in the known numbers results in: 18 = (1/2)b(9) simplify: 18 = 4.5b divide both sides by 4.5: b = 4, so the length of the base is 4 m.
