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M is the midpoint of line segment AB. A has coordinates (3-7) and M has coordinates (-11). What is the coordinates of B?
DenyAllSanity
B is (-5, 9).
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∙ 7y ago
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What is the midpoint of the line segment with endpoints -11 0 and 9 -1?
Points: (-11, 0) and (9, -1) Midpoint: (-1, -1/2)
What is the midpoint of a segment whose endpoints are 12 7 and 8 -11?
The midpoint is at: (10, -2)
What is the difference between a defined and an undefined term in Geometry?
The difference between defined and undefined terms is that the defined terms can be combined with each other and with undefined terms to define still more terms. These are undefined terms: 1.plane 2.point 3.line These are defined terms: 1.ray 2.union of sets 3.space 4.subset 5.set 6.proper subset 7.opposite rays 8.postulate 9.betweenness of points 10.bisector of a segment 11.midpoint of a segment 12.line segment 13.lenght of a segment 14.collinear points 15.complement of a set 16.coplanar points 17.disjoint sets 18.element 19.empy set 20.finite set 21.geometry 22.infinite set 23.intersection of sets
What is the midpoint between the points -1 4 and -2 -9?
-1 + -2 = -3-3/2 = -1.54 + -9 = -5-5/2 = -2.5So the midpoint = (-11/2, -21/2)
What is the perpendicular bisector equation of the line joined by the points 11 13 and 17 19 showing work and answer?
The equation of a line through point (x0, y0) with gradient m is given by:y - y0 = m(x - x0)The gradient (m) of a line between two points (x0, y0) and (x1, y1) is given by:m = change_in_y/change_in_x = (y1 - y0)/(x1 - x0)→ The equation of the line between (11, 13) and (17, 19) is given by:y - 13 = (19-13)/(17-11) (x - 11)→ y - 13 = 6/6 (x - 11)→ y - 13 = x - 11→ y = x + 2and its gradient is m = 1.The gradient (m') of a line perpendicular to a line with gradient m is such that mm' = -1, ie m' = -1/m→ The gradient of the perpendicular line to the line between (11, 13) and (17, 19) has gradient m' = -1/1 = -1.The perpendicular bisector goes through the point midway between (11, 13) and (17, 19) which is given by the average of the x and y coordinates: ((11+17)/2, (13+19)/2) = (14, 16)Thus the perpendicular bisector of the line joining (11, 13) to (17,19) is given by:y - 16 = -1(x - 14)→ y - 16 = -x + 14→ y + x = 30Which in its general form is: x+y-30 = 0
What is the midpoint of the line segment with endpoints -11 0 and 9 -1?
Points: (-11, 0) and (9, -1) Midpoint: (-1, -1/2)
What is the midpoint of the line segment with endpoints (-17) and (3-3)?
Points: (-12, -3) and (3, -8) Midpoint: (-9/2, -11/2) or as (-4.5, -5.5)
What is the midpoint of the line segment with endpoint (-17) and (3-3)?
Points: (-12, -3) and (3, -8) Midpoint: (-9/2, -11/2) or as (-4.5, -5.5)
What is the midpoint of the line segment with endpoints (-1 7) and (3 -3)?
Points: (-12, -3) and (3, -8) Midpoint: (-9/2, -11/2) or as (-4.5, -5.5)
What is midpoint of the line segment with endpoints (-1 7) and (3 -3)?
Points: (-12, -3) and (3, -8) Midpoint: (-9/2, -11/2) or as (-4.5, -5.5)
What is the midpoint of the line segment with endpoints -12 -3 and 3 -8?
Points: (-12, -3) and (3, -8) Midpoint: (-9/2, -11/2) or as (-4.5, -5.5)
What is the midpoint of a segment whose endpoints are 12 7 and 8 -11?
The midpoint is at: (10, -2)
What is the midpoint of a segment whose endpoints are 5 8 and 11 6?
Midpoint: (8, 7)
The midpoint of the coordinates (9 11) and (7 8) is?
To find the midpoint, you find the mean (average) of each direction's coordinates. The average of the x coordinates is (9+7)/2 = 8. The average of y coordinates is (11+8)/2 = 9.5, So the midpoint is (8,9.5). This same method works for 3 and higher dimensions.
A segment has endpoints at -11 12 and 8 -5 What is the x-coordinate of the midpoint of that segment?
-1.5 :]
The length of the transverse axis is 11 and the length of the red line segment is 19 How long is the blue line segment?
8
The length of the red line segment is 8 and the length of the blue line segment is 3 How long is the major axis of the ellipse?
4 11 10.8
