(n - 8)/n = 1/3 3*(n - 8) = n 3n - 24 = n 2n = 24 n = 12 and so n - 8 = 4 4/12 = 1/3
Let first COI=n=3 second COI=n+2=5 third COI=n+4=7 (n)(n+2)=n+4+8 check: n^2+2n=n+12 n^2+n-12=0 -n-12 -n-12 -4^2+(-4)-12=0 n^2+2n-n-12=0 16+(-4)-12=0 n^2+n-12=0 12-12=0 (n+4)(n-3)=0 0=0 n+4=0 n-3= 0 n^2+n-12=0 -4 -4 +3 +3 3^2+3-12=0 n=-4 n=3 9+3-12=0 reject 12-12=0 because is negative and it needs to be positive 0=0
If n is the variable then it's making the two sides equal to one another. So the question is what is n, if n/12 = 20/30 ? First of all 20/30 is 2/3 when that fraction is reduced. Once you have n/12 = 2/3 ... isolate the n, in the equation so... n = (2/3) x 12 .... therefore n = 8. We can prove this by substituting 8 to n .... 8/12 is equivalent to 2/3 whereas 20/30 is equivalent to 2/3. Thus 2/3 = 2/3.
5n - n = 8 + 4 ie 4n = 12 so n = 3
n = 1: -4 + 8 = 4 n = 2: -8 + 8 = 0 n = 3: -12 + 8 = -4 n = 4: -16 + 8 = -8
(N/8)=(12/16) N= (12*8/16) N=6
let number = n n = 2/3 * 12 = 8
n = -35(n+3)/8 = -4Multiply both sides by 8.8(n+3)/8 = -4 x 8Cancel 8 on the left-hand side.8(n+3)/8 = -4 x 8Simplify.n+3 = -32Subtract 3 from both sides.n = -32 - 3Simplify.n = -35
12 - n 4 = 8
n - 3 = -8 Add '3' to both sides n - 3 + 3 = -8 + 3 n = -5 The answer!!!!!
So, 3 + 12 = n + 3. Subtract 3 from both sides of the equation and get 12 = n or n = 12 if you prefer.
8 (again) The sequence is generated by t(n) = (-n3 + 6n2 + 7n - 12)/6 for n = 1, 2, 3, ...