0.3333
When n = 4, 3n = 3*4 = 12
0.3333
16 - n = 4 n = 12
12/n+7m=30 12/6=2 + 7x4=28
N+4=12 Then, you subtract 4 from each side N+4-4=12-4 So, N=8
Let first COI=n=3 second COI=n+2=5 third COI=n+4=7 (n)(n+2)=n+4+8 check: n^2+2n=n+12 n^2+n-12=0 -n-12 -n-12 -4^2+(-4)-12=0 n^2+2n-n-12=0 16+(-4)-12=0 n^2+n-12=0 12-12=0 (n+4)(n-3)=0 0=0 n+4=0 n-3= 0 n^2+n-12=0 -4 -4 +3 +3 3^2+3-12=0 n=-4 n=3 9+3-12=0 reject 12-12=0 because is negative and it needs to be positive 0=0
The answer is a set of the form {4, 4, 6, n, 12} where n is any number between 6 and 12.The answer is a set of the form {4, 4, 6, n, 12} where n is any number between 6 and 12.The answer is a set of the form {4, 4, 6, n, 12} where n is any number between 6 and 12.The answer is a set of the form {4, 4, 6, n, 12} where n is any number between 6 and 12.
14 ! If n=12, then 12-4 is 8, plus 6 is 14
If you mean: -4*(n-6) = 12 then the value of n = 3
(n - 4)(n - 12)
0.3333
When n = 4, 3n = 3*4 = 12
n/4=n-12 So n=4n-48 Therefore -3n=-48 Finally n=16
Yes. Multiplying out the brackets on the second one: 4(n + 3) = 4×n + 4×3 = 4n + 12.
Answer : 3 or 4 Let the number be represented by n. 12 + n2 = 7n : n2 - 7n + 12 = 0 This equation can be factored. (n - 3)(n - 4) = 0 Then either n - 3 = 0, when n = 3 ; or n - 4 = 0, when n = 4 CHECK : 12 + 32 = 12 + 9 = 21 = 7 x 3 12 + 42 = 12 + 16 = 28 = 7 x 4.
Step 1: 4n=12 Step 2: divide both sides by 4 Step 3: 4n/4 = 12/4 Step 4: reduce Step 5: n=12/4 Step 6: n=3