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Find three consecutive odd integers such that the product of the first and the second exceeds the third by 8?
Wiki User
∙ 12y ago
Let first COI=n=3
second COI=n+2=5
third COI=n+4=7 (n)(n+2)=n+4+8 check:
n^2+2n=n+12 n^2+n-12=0 -n-12 -n-12 -4^2+(-4)-12=0
n^2+2n-n-12=0 16+(-4)-12=0
n^2+n-12=0 12-12=0
(n+4)(n-3)=0 0=0
n+4=0 n-3= 0 n^2+n-12=0
-4 -4 +3 +3 3^2+3-12=0
n=-4 n=3 9+3-12=0
reject 12-12=0 because is negative and it needs to be positive 0=0
Wiki User
∙ 12y ago
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The sum of two consecutive integers is -377 What are the integers?
Consecutive means one after another.If the first is a, then the second is a+1.The sum of these isa + a + 1 = 2a+1 = -3772a = -378a = -189So the two numbers are -189 and -188
How do you find consecutive integers?
Consecutive integers could be thought of as counting numbers in a row. One of them is "lowest" and the next one will be one more than that, and the last one will be one more than the second one. The numbers 7, 8 and 9 and 46, 47 and 48 are each said to be three consecutive integers. You often come across a question that tells you that 3 consecutive integers add up to a value. Example 3 consecutive integers add to 6. What are the integers? Let the first integer be x the second is then x +1 the third x+2 add them x+x+1+x+2 =3x+3 and this would be equal to 6. we then have the equation 3x+3=6 3x=3 x=1 so the first integer is 1, the second would be 2 and the third 3
How Find three consecutive even integers such that three times the first integer is six more than twice the second integer?
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Find the smallest of four consecutive even integers if twice the sum of the second and third integers is equal to the sum of the first and fourth integers increased by fourteen?
Since we know that the integers are even and consecutive, we can call them x, x+2, x+4, and x+6, with x being the smallest of the four. twice the sum of the second and third can be written as 2(x+2+x+4)=4x+12 the sum of the first and fourth increased by 14 is x+x+6+14=2x+20 Then we can solve 4x+12=2x+20-->2x=8-->x=4 4
What three consecutive positive even integers such that the product of the second and third integers is twenty more than ten times the first integer?
10-11-12
What is the second integer if three consecutive integers have the sum of 153?
51
What are the three consecutive integers if the sum of the second and thrid exceeds a half of the first by thirty-three?
Let the three consecutive integers be n, n + 1 and n + 2. Then (n + 1) + (n + 2) = n/2 + 33 2n + 3 = n/2 + 33 : 4n + 6 = n + 66 : 3n = 60 : n = 20 The three numbers are 20, 21 and 22.
The sum of two consecutive even integers is 50 what is the first number?
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Find 3 consecutive even integers if the product of the first integer and two two less than the second integer is four more than five times the third integer and what is the let statement?
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The sum of two consecutive integers is -377 What are the integers?
Consecutive means one after another.If the first is a, then the second is a+1.The sum of these isa + a + 1 = 2a+1 = -3772a = -378a = -189So the two numbers are -189 and -188
Find four consecutive integers such that the sum of the second and fourth is 132?
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What is the sum of two consecutive integers have the sum of 275?
I assume you mean what are the two consecutive integers. Algebraically; X = integers.X + (X + 1) = 2752X + 1 = 2752X = 274X = 137============solution setorSince the consecutive integers differ by 1, then the first number is 274/2 = 137, so the second one is 1 more, 138.
How do you find consecutive integers?
Consecutive integers could be thought of as counting numbers in a row. One of them is "lowest" and the next one will be one more than that, and the last one will be one more than the second one. The numbers 7, 8 and 9 and 46, 47 and 48 are each said to be three consecutive integers. You often come across a question that tells you that 3 consecutive integers add up to a value. Example 3 consecutive integers add to 6. What are the integers? Let the first integer be x the second is then x +1 the third x+2 add them x+x+1+x+2 =3x+3 and this would be equal to 6. we then have the equation 3x+3=6 3x=3 x=1 so the first integer is 1, the second would be 2 and the third 3
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If the first of these consecutive integers is x, the second integer would be x + 1, and the third integer would be x + 2.Since the sum of the second and the third integer is 17, we can writex + 1 + x + 2 = 172x + 3 = 172x + 3 - 3 = 17 - 32x = 142x/2 = 14/2x = 7Thus, the consecutive integers are 7, 8, and 9.
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What are the 2 consecutive integers such that the sum of one-third the first and one-fourth the second is 9?
-7
