You forgot to enter the total age. But that's OK. We can solve this puzzle in general. Let A = Andy's age now. Let K = Kate's age now. Then your problem statement can be written A = 2K (A+6) + (K+6) = T , where T is the total of the ages in 6 years. Then, substituting 2K for A in rthe second equation, we have 2K+6 + K+6 = T, or 3K = T-12 Here is a table of solutions for various T ("Total age in six years"): T A K ---- 15 2 1 18 4 2 21 6 3 24 8 4 ... 48 24 12 51 26 13 etc.
The ages are 8 and 4
Total ages at present = 42 Total ages in 10 years = 52 Fractions then 15/26 x 52 and 11/26 x 52, ie 30 and 22 so ages now 25 and 17
beth is 5 years old.
7
The greatest common factor of their ages is 1.
He is 67.
The boy is 9 years old and his sis is 18 years old
A is 35 years old, B is 15 years old.
32
Joe is 20.
42/4 = 10.510.5*3=31.5
Sarah is 76, Margaret is 38, Jenny is 19. S + M + J = 133 S + 1/2S + 1/4 S = 133 7/4 S = 133 S = 76