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182 is the product of 2 consecutive integers but the answer is not unique?

The numbers are 13 and 14.


The product if two consecutive integers is 182?

13 x 14 = 182


What are two consecutive integers that have a product of 182?

13 and 14


Find two consecutive negative integers whose product is 182?

-13*-14 = 182


Is the product of any two integers an integer?

Yes, the product of 2 integers are always an integers. ex. -2*3=-6


Find two consecutive integers that have a product of 182?

13 and 14. Also negative 13 and negative 14.


Two integers have a difference of -18 and a sum of 2 What is the product of the two integers?

The product of the two integers is -80.


Two consecutive integers for 182?

13 x 14 = 182


What are 2 consecutive numbers that are equal to 182?

There are two consecutive even integers: 90 and 92.


What are two consecutive integers have a product of 182?

One way to find out is write a formula. Let N and N+1 be the two integers, then N(N+1) = 182 N^2 + N - 182 = 0 This is a quadratic equation. If the factors are not obvious, (N -13)(N + 14) , then use the quadratic formula to find N. The factors tell you there are two possible solutions for N; 13 and -14. Now add 1 to these to get the two consecutive integers. 13 & 14 will work and -14 & -13 will work.


Find two consecutive integers that have products of 182?

The integers are 13 and 14.


What is a counterexample to this conjecture the sum of any two integers that are greater then 1 is less then their product?

A counterexample to the conjecture that the sum of any two integers greater than 1 is less than their product is the pair (2, 2). The sum of these integers is 2 + 2 = 4, while their product is 2 × 2 = 4. Here, the sum equals the product, demonstrating that the conjecture does not hold for all integers greater than 1.