A rectangle has 4 sides.
Let the width of the rectangle be y.
As the length of the rectangle is twice its width, it is 2y.
The sum of the 2 sides that are the width: 2 * y = 2y
The sum of the 2 sides that are the length: 2y * 2 = 4y
The perimeter equals the 2 widths and the 2 breadths: 2y + 4y = 6y
The perimeter: 6y = 60 cm
So: y = 10 cm
The length is 2y = 2 * 10 cm = 20 cm
Answer: 20 cm
A=392
2x2=392
x2=196
x=14
50
The length of a rectangle is twice its width. If the perimeter of the rectangle is , find its area.
2x4
L=16 in W=8 in
156 It is impossible to calculate the area of a rectangle from its perimeter if no other dimension is known. The area of a rectangle is the product of its length and width, and the perimeter is twice the sum of its length and width.
Area is length times width, perimeter is twice the sum of length and breadth.
The width is 6 cm and the length is 12 cm.
98 square feet
It is: 10 times 5 = 50 square in
The area of a rectangle is calculated by multiplying the length by the width. The formula for the area of a rectangle is Area = Length x Width.
8 ft.
From the statement of the problem, if w is the width, the area is 2w2 , the product of the width and the length, which is stated to be twice the width. Since 2w2 must be less than 50, w2 < 25, and the width must be less than 5 meters.
50 cm2