3x + 4y = 12 subtract 3x to both sides
4y = -3x + 12 divide by 4 to both sides
y = (-3/4)x + 3 directly we say that y-intercept is 3, to find x-intercept assigning y to 0;
0 = (-3/4)x + 3
-3 = (-3/4)x multiply by -4/3 to both sides
(-3)(-4/3) = (-3/4)(-4/3)x
4 = x the x-intercept is 4
If you mean 3x+4y = 12 then the x intercept = 4 and the y intercept = 3
-8
5
3x - 4y = 24At the x-intercept, y=0 :3x = 24x = 8At the y-intercept, x=0 :-4y = 24y = -6
11
3x - 5y = 45At the y-intercept, x = 0.-5y = 45y = -9At the x-intercept, y = 0.3x = 45x = 15
y intercept 7 x intercept 7/3
-3x + 5y = -15At the x-intercept, y=0:-3x = -15 . . . . . x = 5At the y-intercept, x=0:5y = -15 . . . . . y = -3
3x + y = 12The x intercept occurs when y = 0. Then, 3x + 0 = 12 : 3x = 12 : x = 4The y intercept occurs when x = 0. Then, (3 x 0) + y = 12 : y = 12.
X intercept is the value of X when Y = 0 -5Y + 3X = 12 ley Y = 0 3x = 12 x = 4
2
If you mean: -3x+5y = 30 then the x intercept is at (-10, 0) and the y intercept is at (0, 6)