y intercept 7
x intercept 7/3
If: 6y-3x = 18 Then: y = 0.5x+3 which is in slope-intercept form
-3x + 2y = 8To get into slope intercept, we must set the equation equal to y2y = 3x + 8y = 3/2x + 8/2y = 3/2x + 4
The slope-intercept form of the equation of a line is y = mx + b, where m is the slope and b is the y-intercept. To put 3x - 2y = 16 in slope-intercept form just requires a little rearranging: 3x - 2y = 16 -2y = -3x + 16 (subtract 3x from both sides) y = 3/2x - 8 (divide all terms by -2) Now the equation is in slope-intercept form. The slope m is 3/2; the y-intercept is -8.
same x intercept as y = 3x -9 x intercept is when y = 0 0 = 3x-9 3x = 9 x = 3, the same x intercept Now find the line parallel to 3x+y = 0 with x intercept = +3 Since line is parallel it has the same slope 3x+y = 0 y = -3x +0 standard form where the number in front of x is slope, = -3 Thus y = -3x + b but we know x intercept (when y = 0) is +3 0 = -3(3) + b solve b = +9 the parallel line is y = -3x+9
slope: -3 y-intercept: 9
the slope is -3 and the y-intercept is (0,4)
3x + y = 5 y = -3x + 5 slope is -3 and y intercept is 5.
If: -3x+2y = 12 Then: y = 1.5x+6 in slope-intercept form
y-intercept is 10 slope is 3 over 1
y = 3x + 3 is the 'slope/intercept' form. In the general eq'n of a straight line ; y = mx + c ; The slope(m) is the coefficient of 'x' and the constant(c) is the intercept on the y-axis. So for the given eq'n , The slope is '3' and and the intercept is also '3'.
If: 3x+y = 16 Then: y = -3x+16 whereas -3 is the slope and 16 is the y intercept
If: 3x-5y+10 = 0 Then: -5y = -3x-10 And: y = 0.6x+2 in slope-intercept form
It is 3 and the slope is 3/5
3x+4y = 4 4y = -3x+4 y = -3/4x+1 So the slope is -3/4 and the intercept is 1