y intercept 7 x intercept 7/3
Assuming the equation is 3x + y = 15, then the x-intercept is (5, 0) and the y-intercept is (0, 15).
same x intercept as y = 3x -9 x intercept is when y = 0 0 = 3x-9 3x = 9 x = 3, the same x intercept Now find the line parallel to 3x+y = 0 with x intercept = +3 Since line is parallel it has the same slope 3x+y = 0 y = -3x +0 standard form where the number in front of x is slope, = -3 Thus y = -3x + b but we know x intercept (when y = 0) is +3 0 = -3(3) + b solve b = +9 the parallel line is y = -3x+9
To find the y-intercept, we set x to 0. 3*0+8y=24 8y=24 y=3 To find the x-intercept, we set y to 0. 3x+8*0=24 3x=24 x=8
3x + y = 12The x intercept occurs when y = 0. Then, 3x + 0 = 12 : 3x = 12 : x = 4The y intercept occurs when x = 0. Then, (3 x 0) + y = 12 : y = 12.
X intercept is the value of X when Y = 0 -5Y + 3X = 12 ley Y = 0 3x = 12 x = 4
y intercept 7 x intercept 7/3
y intercept (0,2) x intercept (-2/3, 0)
x intercept: -4 1/3 y intercept: 13
-3x + 5y = -15At the x-intercept, y=0:-3x = -15 . . . . . x = 5At the y-intercept, x=0:5y = -15 . . . . . y = -3
x intercept = 5 y intercept = 15
The x intercept would be 14 and the y intercept would be 6.
Assuming the equation is 3x + y = 15, then the x-intercept is (5, 0) and the y-intercept is (0, 15).
same x intercept as y = 3x -9 x intercept is when y = 0 0 = 3x-9 3x = 9 x = 3, the same x intercept Now find the line parallel to 3x+y = 0 with x intercept = +3 Since line is parallel it has the same slope 3x+y = 0 y = -3x +0 standard form where the number in front of x is slope, = -3 Thus y = -3x + b but we know x intercept (when y = 0) is +3 0 = -3(3) + b solve b = +9 the parallel line is y = -3x+9
X intercept: -5 Y intercept: +3
3x + 4y = 12 subtract 3x to both sides4y = -3x + 12 divide by 4 to both sidesy = (-3/4)x + 3 directly we say that y-intercept is 3, to find x-intercept assigning y to 0;0 = (-3/4)x + 3-3 = (-3/4)x multiply by -4/3 to both sides(-3)(-4/3) = (-3/4)(-4/3)x4 = x the x-intercept is 4
1 and 2