because... odd+odd=even even+odd=odd e.g 1+1+1=3 odd+odd+odd=odd
0.0667
yes, the product of 2 odd numbers is always an odd number. Well, the question is why. The first number is "even" + 1. Multiply both of these by your odd number. Now the "even" times "odd" is even, because every "1" in the odd number becomes a "2". And then the remaining 1 times "odd" must be odd, which is an even +1. Add it all up and you get evens everywhere except that final "1". So the result is even + 1 which is odd. There is a quicker way if you know how to multiply bracketed terms: odd x odd = (even + 1)x(even +1)= even x even +even +even +1 = must be odd.
It is odd. The definition of an odd number is "a number a is odd if there exists an integer n such that a = 2n + 1." Let a = 1 and let n = 0, so 1 = (2x0) + 1.
67/1 To make any whole number a fraction, put it over 1.
Odd. It ends with a 1, which is an odd number.
odd
Answer:1 is an odd number If you need to learn math go to the web site in the link below
No. The sum of 1 odd number and 1 even number must always be odd.
The simple explanation is based on the two rules: Odd+Odd = Even and Even+Odd = Odd Adding the first two Odd numbers (rule 1) gives an Even number. Then adding the Odd (rule 2) gives the Odd final answer. The mathemetical proof goes as follows: An odd number is one that, when divided by 2, leaves a remainder of 1. So, as odd number can always be written in the form 2x + 1 where x is an integer. Now suppose 2a+1, 2b+1 and 2c+1 are three odd numbers where a, b and c are integers. (They need not all be different). Then their sum is 2a+1+2b+1+2c+1 = 2a+2b+2c+2+1 = 2(a+b+c)+1 which is of the same form as 2x+1 (with a+b+c replacing x).
.067 = 67/1000 which cannot be reduced further.
that's an odd question. One is an odd number.