0
Add your answer:
Earn +20 pts
If the sum of two numbers is 6 and there difference is -2 what are the two numbers?
Let numbers be x and y. Then, x + y = 6 x - y = -2 add up both equations 2x + y - y = 6 + (-2) 2x = 4 divide by 2 to both sides x = 2 Since the sum of the numbers is 6 and one of the numbers is 2, then the other number is 4 (6 - 2). Check: 2 + 4 = 6 2 - 4 = -2
What is the prime factorization of 252?
The "shortened" prime factorization of 252 is 22*32*7; the "longer" is 2*2*3*3*7.
5x squared - 7x squared?
When you subtract 7x^2 from 5x^2, you get -2x^2.
What do you do with c squared and b squared to get a squared?
You add c squared and b squared together to get a squared. This is based on the Pythagorean theorem, which states that in a right triangle, the square of the hypotenuse (a) is equal to the sum of the squares of the other two sides (b and c).
Who invented edmodo?
If you log into your account, go to your profile. Replace the ID number with "1" - Judging from the profile ID of 1, Mr. Borg invented Edmodo and was the first person on the website. -
Log x plus log 2 equals log 2?
log(x) + log(2) = log(2)Subtract log(2) from each side:log(x) = 0x = 100 = 1
Log 2 plus log 4 equals log 2x?
log(2) + log(4) = log(2x)log(2 times 4) = log(2x)2 times 4 = 2 times 'x'x = 4
If 3 log x - 2 log y?
1
How do you solve 3 to the power of negative 2x plus 2 equals 81?
3^(-2x + 2) = 81? log(3^(-2x + 2)) = log(81) (-2x+2)log(3) = log(81) -2x = log(81)/log(3) - 2 x = (-1/2)(log(81)/log(3)) + 1
How do you solve log base 2 of x - 3 log base 2 of 5 equals 2 log base 2 of 10?
[log2 (x - 3)](log2 5) = 2log2 10 log2 (x - 3) = 2log2 10/log2 5 log2 (x - 3) = 2(log 10/log 2)/(log5/log 2) log2 (x - 3) = 2(log 10/log 5) log2 (x - 3) = 2(1/log 5) log2 (x - 3) = 2/log 5 x - 3 = 22/log x = 3 + 22/log 5
Which expressions are equivalent to the one below log 2 - log 4?
-2
Given log 2 and log 3 how do you compute log 36?
log(36) = 1.5563To solve this problem without using a scientific calculator, factor 36 into 2*2*3*3, and use the formula:log(a*b) = log(a) + log(b)So, in this case:log(36) = log(2) + log(2) + log(3) + log(3) = 0.3010 + 0.3010 + 0.4772 + 0.4772 = 1.5564 (slight rounding error)
How do you solve log x plus 2 equals log 9?
log x + 2 = log 9 log x - log 9 = -2 log (x/9) = -2 x/9 = 10^(-2) x/9 = 1/10^2 x/9 = 1/100 x= 9/100 x=.09
Log base 2 of x - log base 2 of x-23?
log base 2 of [x/(x - 23)]
What are the rules when squaring a log squaring the whole log?
this is the question (log (base2) (x))^2- 12(log (base 2) (x)) + 32 = 0, I don't get this bit (log (base2) (x))^2, note the whole log is squared
Why is the answer for log x squared equals 2 different than 2log x equals 2?
log x2 = 2 is the same as 2 log x = 2 (from the properties of logarithms), and this is true for x = 10, because log x2 = 2 2 log x = 2 log x = 1 log10 x = 1 x = 101 x = 10 (check)
Which expressions are equivalent to log 2 - log 8?
-6
