first you multiply 33333333334 by 33333333334 (if its kinda hard to count these, they both have ten 3's, and one 4) and then you should get this: 1111111111155555555556 (for this one, there are eleven 1's, ten 5's, and one 6) then you add all these digits together, and should get this: 67 ***p.s. the reason why it's not 1156 is because, in the order of operations, you have to solve the exponents (to the second power) before you can start adding***
Straight line depreciation method allocate equal amount for all years while in sum of years digit method depreciation is allocated with high amount in initial years while low amount in later years.
A binary number is a number expressed in base-2 numeral system, which uses only two digits: 0 and 1. When you say "of eight," it is unclear what you are referring to. If you are asking about the digit 8 in binary, it is represented as 1000.
I've been trying to figure this out myself for a discrete structure class.From the digging I've done online I've found this formula thus far:if n is the number of digits, and s is the sum:C(n+s-1 , n-1) where C denotes "choose" as in C(n , k) "n choose k" which can be solved by(n! / [ (n-k)! * k! ] )this seems to work for situations where the sum is < 10, or so claims the forum I found.I whipped it all up into a scheme function if anyone wants to take advantage:;;factorial: num -> num;;finds factorial of num.(define (factorial num)(if (or (= num 1) (= num 0))1(* num (factorial (sub1 num)))));;==========================;;xchy: num num -> num;;the "n choose k" function(define (xchy n k)(/ (factorial n)(* (factorial(- n k))(factorial k))));;==========================;;n-dig&sum-s: num num -> num;;finds the number of n digit combinations with sum s;;C(n+s-1,n-1)(define (n-dig&sum-s n s)(xchy (sub1 (+ n s))(sub1 n)))
go to http://www.examscouncil.or.ke or on your phone type KCSE followed by the nine digits of the candidate's index number e.g. KCSE 713403xxxthen send to 2228 for both zain and safaricom charged at 20 bob per message
5600
The number would be 2666. 6 is repeated 3 times. Rounded to the nearest hundred is 2700 and rounded to the nearest thousand is 3000.
199
648 rounded to the nearest hundred is 600.
27222722
278879 rounded to the nearest hundred - is 278900. The last two digits (79) are greater than 50 so you round up.
1400
6700
2722
863.00
To round to the nearest hundred and ten both being 200 it leaves 9 possibilities. 195,196,197,198,199,201,202,203, and 204. The only one with digits adding up to 19 is 199.
500