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a 220 volt, 3200 watt oven will draw under 15 amps, so yes a 2o amp breaker will work.
50 amp with AWG # 6 wire is normal. Read the instructions that came with the stove to make sure.
A sauna heating element is a resistive load. The equation that you are looking for is Amps = Watts/Volts = 8000/220 = 36 amps. A #8 copper conductor with an insulation rating of 90 degrees C is rated at 55 amps. This will be fed with 40 amp two pole breaker.
I think you mean 2 HP pump. I am assuming a 220 To 240 volt supply and that should equate to about a 12 amp current. All my pumps use only a 30 amp breaker and 10 AWG wire.
Can you supply three 220 -240 volt 16.6 amp infrared heaters with one circuit?
a 220 volt, 3200 watt oven will draw under 15 amps, so yes a 2o amp breaker will work.
For a 240-volt circuit that requires a 50 amp breaker, the appropriate size of the breaker needed is 50 amps.
The maximum current capacity of a 220 volt 20 amp outlet is 20 amps.
If it is a 30 amp breaker then it is a 240 volt outlet.
No, a double 30 amp breaker means you have a total of 30 amps available for each leg of the 220 volt outlet. So, in total, you have 60 amps available for the outlet (30 amps on each leg).
50 amp with AWG # 6 wire is normal. Read the instructions that came with the stove to make sure.
If you are using typical residential voltages ( 120v/240v) a 40 amp breaker is plenty big enough. You could even use a twenty amp breaker.
It is not recommended to replace a 20 amp breaker with a 30 amp breaker for a 220 volt machine. The breaker size needs to be compatible with the current draw of the machine to ensure safe operation and prevent electrical hazards. Using a larger breaker than recommended could lead to overheating and potentially damage the machine or cause a fire hazard.
The recommended wire size for a 30 amp 220 volt circuit is typically 10 gauge wire.
The appropriate wire size for a 220 volt 30 amp circuit is typically 10 gauge wire.
No. If your AC is currently running on a 30 amp 2 pole breaker, then it is a 220 volt unit. You cannot substitute one 60 amp single pole breaker as you'll only be supplying 110 volts and the AC unit won't work. In fact you could damage it.
A sauna heating element is a resistive load. The equation that you are looking for is Amps = Watts/Volts = 8000/220 = 36 amps. A #8 copper conductor with an insulation rating of 90 degrees C is rated at 55 amps. This will be fed with 40 amp two pole breaker.