First let's write it as a sum of powers of two. This will make it easier to write as a binary number. 19=16+2+1 This can be written: 19=16*1+8*0+4*0+2*1+1*1 So the binary form is: 10011
answer is 0 10000011 00111000000000000000000 to get it first we have to convert 19.5 to binary 19 ->10011 ( 1* 2^4+1*2^3+1*2^2+1*2^1+1*2^0) 0.5-> 0.1 (2^-1=0.5) 10011+0.1=10011.1 The next step is to normalize this number so that only one non zero decimal place is in the number. To do this you must shift the decimal place4 positions to the left. The number4 becomes important so we note it. This process leaves us with the number 1.00111 which is the fraction that is represented in the last 23 bit places in the 32 bit binary. This is then padded with 0's to fill in the full 23 bits - leaving us with 00111000000000000000000. so now we have first digit as 0 because this z a positive no and the last 23 digits. We must now derive the middle 8 bits. To do this we take our exponent (4) and add 127 (the maximum number you can express with 8 bits (2^8-1 or the numbers 0 to 127)) which gives us 131. We then express this number as an 8 bit binary. This is 10000011 (or 1*2^7 + 1*2^1+ 1*2^0 or 128+2+1). Now we have the middle bits. Taken as a whole our bit sequence will be: 0 10000011 00111000000000000000000
I do not know a specific formula to do it. but its very simple. really really simple lets get a binary code = 10011101 now, we are going to convert this to decimal. You should start it from the last binary number in the given code,(right hand corner) then multiply that number from 2 to the power of 0( 2^0) 1* (2^0) = 1* 1 = 1 --------- (A) then we go to the next binary number. (which is 0 in this case) now we must multiply this from 2 to the power 1. (2^1); 0 * (2^1) = 0* 2 = 0 --------(B) do this sequentially till the first number. (multiplying from 2^2,2^3,...,2^7) similarly you get, 1 * (2^2) = 4 ----(C) 1 * (2^3) = 8 ----(D) 1 * (2^4) = 16 ----(E) 0 * (2^5) = 0 ------(F) 0 * (2^6) = 0-----(G) 1 * (2^7) = 128----(H) now, add the values you got in equation A,B,C,D,E,F,G,H 1+0+4+8+16+0+0+128 = 157; so this is the decimal number for the given binary code. hope you got it!!
#include #includevoid main(){int a[20],b,c,d,i=0;printf("Enter a decimal no. to convert it into binary no.");scanf("%d",&b);c=b;while(b>0){d[i]=b%2;i++;b=b/2;}i--;printf("\nBinary equivalent of decimal no. %d is ",c);while(i>=0){printf("%d",d[i]);i--;}getch();}
(10011)2 = (19)10
Binary Number System represents the way Computer understands the instructions or data. Binary is the primary way humans can save data in Physical form, such as Land & Pits on Optical Media (CDs or DVDs).Computer interprets these binaries (collectively as BYTES - 8 bits) as instructions or data to perform its functions.So Binary system is the method of writing instructions & data for Computers.
10011
10011.
19
19 in binary is... 10011 (16+2+1)
it is itself in a binary form :) but if its in decimal form.. then its binary equivalent will be..(10011100011011) if it is in binry form.. its equivalent will be..(19)
the sum of (1001+1010)is=(10011)
10011 = 1*24 + 0*23 + 0*22 + 1*21 + 1*20 = 16 + 0 + 0 + 2 + 1 = 19
10011 binary or 19 in decimal.
First let's write it as a sum of powers of two. This will make it easier to write as a binary number. 19=16+2+1 This can be written: 19=16*1+8*0+4*0+2*1+1*1 So the binary form is: 10011