Q: Convert the hexadecimal number BB895C to octal and Decimal?

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A45C: Decimal = 42076 Octal = 122134

This is not a question.

FC(16) = value_of(F)*16 + value_of(C) = 15*16+12 = 252

16 is the 4th power of 2. So a hexadecimal number is converted to binary by replacing each hex digit by the 4-bit binary number having the same value. Conversely, in converting binary to hexadecimal, we group every 4 bits starting at the decimal (binary?) point and replace it with the equivalent hex digit. For example, the hexadecimal number 3F9 in binary is 1111111001, because 3 in binary is 11, F (decimal 15) is 1111, and 9 is 1001.

0X at the beginning represent a number in the hexadecimal system of units. FFFF is the hexadecimal equivalent of i) 65535 in decimal system of units ii) 1111111111111111 in binary system of units

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56704534

Octal: 56704534 Decimal: 12290396

224 = E0

NA

A45C: Decimal = 42076 Octal = 122134

pongada punda vayanungala ..................

221122: Binary = 1000100001000100100010 Octal = 10410442 Decimal = 2232610

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BA = 11*16 + 10 = 176 + 10 = 186

Whether or not you can do that depends on the size of the number. If the number in question is greater than [decimal] 66535, then you cannot.

10011101: Decimal = 157 Hexadecimal = 9D

The way I convert between decimal and hexadecimal is to first convert the decimal number to binary: 664062510 = 110010101010011111100012 Then split the binary number into 16-bit (4 digit) chunks: 0110 0101 0101 0011 1111 00012 Next, convert each chunk into a hexadecimal digit: 0110 0101 0101 0011 1111 00012 6 5 5 3 F 1 Finally, put all the digits together: 664062510 = 6553F116