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Could you have a quadratic function with one real root and one complex root?
Wiki User
∙ 14y ago
Provided some of the coefficients and the constant were imaginary (complex) as well, yes. For example, (x + 2)(x - 3+i) has both a real and an imaginary root, and has coefficients that are also both real and imaginary, i.e. 1, -1+i, and -6+2i.
Wiki User
∙ 14y ago
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Draw an algorithm amd flowchat to claculate the roots of quadratic equation Ax2 Bx C0?
READ values of a, b and c,if a is zero then stop as we do not have a quadratic,calculate value of discriminantif D is zero then there is one root: ,if D is > 0 then there are two real roots: and ,if D is < 0 there are two complex roots: and ,PRINT solution.
How do you convert integer to objects in c?
There are no objects in C, so you can't. However, in C++ you can convert an integer to an object if the object's class exposes a public conversion constructor that accepts an integer argument. For example: class X { public: X (int); // conversion constructor // ... }; How the conversion is implemented depends on the class designer. In the following example, a user can construct a complex number type from an integer: class complex { private: double r; double i; public: complex (double real, double imaginary): r {real}, i {imaginary} {} complex (int real): r {real}, i {0.0} {} // ... }; Here, the implementation implicitly converts the integer to a double and assigns that value to the real representation and assigns the value 0.00 to the imaginary representation. This class may be used as follows: complex c = 42; // e.g., c.r = 42.0, c.i = 0.0 If a conversion constructor is provided, a corresponding conversion assignment is usually provided as well: class complex { private: double r; double i; public: complex (double real, double imaginary): r {real}, i {imaginary} {} complex (int real): r {real}, i {0.0} {} complex& operator= (int real) { r = real; i = 0.0; } // ... }; This class may be used as follows: complex c {1.1, -3.14}; // ... c = 42; // e.g., c.r = 42.0, c.i = 0.0
What are complex data types?
The standard library provides a complex number type that encapsulates both the real and imaginary parts of a complex number. All arithmetic operators are overloaded to cater for the complex type: #include<iostream> #include<complex> int main() { std::complex<double> c {3.14, 4.2}, d {2.1, -1.2}; std::cout << c + d << std::endl; }
What is a complex data structure?
A complex data structure is the kind of structure that has two arrays. One array hols the real part of the complex data and the other array holds the imaginary part.
Is poop a real life miracle?
No, poop is a body function in which food is transformed. This is NOT a real life miracle.
Can you have quadratic function with one real root and are complex root?
Yes, but in this case, the coefficients of the polynomial can not all be real.
What is Nature of the zeros of a quadratic function?
If you have a quadratic function with real coefficients then it can have: two distinct real roots, or a real double root (two coincidental roots), or no real roots. In the last case, it has two complex roots which are conjugates of one another.
Could you have a quadratic function with one real root and one complex root Think about what the graph of that function might look like. What might the function itself look like?
Yes; to have a quadratic function with two given roots, just decide what roots you want to have - call them "a" and "b" - and write your function as:y = (x - a) (x - b) You can multiply this out if you wish, to make it look like a standard quadratic function. Note that "a" and "b" can be any complex numbers. Graphing such a function is quite complicated; to graph both the x-value and the y-value, each of which is itself a complex (i.e., two-dimensional) number, you really need four dimensions.
Can you have a quadratic function with one real root and one complex root?
No you can not. Complex roots appear as conjugates. if a root is complex so is its conjugate. so either the roots are real or are both coplex.
Could there be a quadratic function that has an undefined axis of symmetry?
Yes and this will happen when the discriminant of a quadratic equation is less than zero meaning it has no real roots.
Are there no real solutions if a quadratic function is 0?
If a quadratic function is 0 for any value of the variable, then that value is a solution.
What does it mean when the graph of a quadratic function crosses the x axis twice?
When the graph of a quadratic crosses the x-axis twice it means that the quadratic has two real roots. If the graph touches the x-axis at one point the quadratic has 1 repeated root. If the graph does not touch nor cross the x-axis, then the quadratic has no real roots, but it does have 2 complex roots.
Where can i find a real-life application of a quadratic function?
Quadratic functions are used to describe free fall.
Do quadratic equations always have two real solutions?
No. A quadratic may have two identical real solutions, two different real solutions, ortwo conjugate complex solutions (including pure imaginary).It can't have one real and one complex or imaginary solution.
When can a quadratic function have an inverse?
It depends on the domain and codomain. In complex numbers, that is, when the domain and codomain are both C, every quadratic always has an inverse.If the range of the quadratic in the form ax2 + bx + c = 0 is the set of real numbers, R, then the function has an inverse if(a) b2 - 4ac ≥ 0and(b) the range of the inverse is defined as x ≥ 0 or x ≤ 0
How are the real solutions of a quadratic equation related to the graph of the quadratic function?
The real solutions are the points at which the graph of the function crosses the x-axis. If the graph never crosses the x-axis, then the solutions are imaginary.
Does a quadratic function have to have 2 x-values?
If you mean have 2 different real x-value solutions then no.Otherwise a quadratic function will always have 2 solutions, just that they may both be the same value (repeated root) making it seem like there is only one solution value, or non-real (complex) making it seem like it has no solution value.
