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If a quadratic function is 0 for any value of the variable, then that value is a solution.
What else can I help you with?
How can you have one solution in something that is quadratic?
b^2 - 4ac, the discriminant will tell you that a quadratic equation may have one real solution( discriminant = 0 ) , two real solutions( discriminant > 0 ), or no real solutions( discriminant < 0 ).
What is the solutions to a quadratic function?
The solutions to a quadratic function, typically expressed in the form ( ax^2 + bx + c = 0 ), can be found using the quadratic formula: ( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} ). These solutions, also known as the roots, represent the x-values where the quadratic function intersects the x-axis. The discriminant ( b^2 - 4ac ) determines the nature of the solutions: if it's positive, there are two distinct real roots; if it's zero, there is one real root; and if negative, there are two complex roots.
How many real solutions does the following quadratic equation have by using the discriminant?
If the discriminant > 0 then 2 distinct real solutions.If the discriminant = 0 then 1 double real solution.If the discriminant < 0 then no real solutions (though there are two complex solutions).
When is there no real solutions for a quadratic equation?
It's when ax2+bx+c=0 if b2-4ac= is negative
What is the discriminant to determine how many real number solutions the quadratic equation -4j2 plus 3j-28 equals 0 has?
The discriminant is -439 and so there are no real solutions.
If the discriminant of a quadratic equation is -4 how many solutions does the equation have?
If the discriminant of a quadratic equation is less then 0 then it will have no real solutions.
How can you have one solution in something that is quadratic?
b^2 - 4ac, the discriminant will tell you that a quadratic equation may have one real solution( discriminant = 0 ) , two real solutions( discriminant > 0 ), or no real solutions( discriminant < 0 ).
What is the solutions to a quadratic function?
The solutions to a quadratic function, typically expressed in the form ( ax^2 + bx + c = 0 ), can be found using the quadratic formula: ( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} ). These solutions, also known as the roots, represent the x-values where the quadratic function intersects the x-axis. The discriminant ( b^2 - 4ac ) determines the nature of the solutions: if it's positive, there are two distinct real roots; if it's zero, there is one real root; and if negative, there are two complex roots.
How many real solutions does the following quadratic equation have by using the discriminant?
If the discriminant > 0 then 2 distinct real solutions.If the discriminant = 0 then 1 double real solution.If the discriminant < 0 then no real solutions (though there are two complex solutions).
How many solution will there be if the quadratic equation does not touch or cross the x-axis?
0 real solutions. There are other solutions in the complex planes (with i, the imaginary number), but there are no real solutions.
When is there no real solutions for a quadratic equation?
It's when ax2+bx+c=0 if b2-4ac= is negative
What is the discriminant to determine how many real number solutions the quadratic equation -4j2 plus 3j-28 equals 0 has?
The discriminant is -439 and so there are no real solutions.
Why do quadratic equations where the discriminant is 0 have exactly 1 real solution?
Suppose the quadratic equation is ax^2 + bx + c = 0 and D = b^2 - 4ac is the discriminant. Then the solutions to the quadratic equation are [-b ± sqrt(d)]/(2a). Since D = 0, the both solutions are equal to -b/(2a), a single real solution.
What statement must be true of an equation before you can use the quadratic formula to find the solutions?
The quadratic formula can be used to find the solutions of a quadratic equation - not a linear or cubic, or non-polynomial equation. The quadratic formula will always provide the solutions to a quadratic equation - whether the solutions are rational, real or complex numbers.
What is x2 -2x plus 2 equals 0?
It is a quadratic equation with no real roots or real solutions. In the complex domain, the solutions are 1 +/- i where i is the imaginary square root of -1.
How many real solutions are there for the equation x2 plus 3x plus 5 equals 0?
There are no real solutions because the discriminant of the quadratic equation is less than zero.
Can there be a real and imaginary solution to a quadratic equation?
Yes, there can be a pure imaginary imaginary solution, as i2 =-1 and -i2 = 1. Or there can be a pure real solution or there can be a complex solution.For a quadratic equation ax2+ bx + c = 0, it depends on the value of the discriminant [b2 - 4ac], which is the value inside the radical of the quadratic formula.[b2 - 4ac] > 0 : Two distinct real solutions.[b2 - 4ac] = 0 : Two equal real solutions (double root).[b2 - 4ac] < 0 : Two complex solutions; they will be pure imaginary if b = 0, they will have both real and imaginary parts if b is nonzero.
