Loop through some numbers - for example, 2 through 100 - and check each one whether it is a prime number (write a second loop to test whether it is divisible by any number between 2 and the number minus 1). If, in this second loop, you find a factor that is greater than 1 and less than the number, it is not a prime, and you can print it out.
Yes
for arrays you can list the different arrays and what attributes that you give to them.
First of all, it's "JDK", not "jdk", and "Java", not "java". What do you mean by "Java new edition"? I do not find that term when I Google for it. "Java 2 SE" is a brand name for very old, obsolete versions of Java, between version 1.2 and 1.4, inclusive. The current version of "Java SE" (Java Standard Edition), as it is now called, is version 7, with support still available for version 6. These versions are also called 1.7 and 1.6, respectively. See <http://www.oracle.com/technetwork/java/javase/jdk7-naming-418744.html>
One way to do this is to convert the number to a String, then use the corresponding String method to find out the length of the String.
Find a prime number, add 2 to the number. Check if the new number is prime. IE : 3 is prime. 3+2 =5. 5 is prime. (3,5) are twin primes.
/* Program to Find whether number is Prime or Not. */ class PrimeNo{ public static void main(String args[]){ int num = Integer.parseInt(br.readLine()); int flag=0; for(int i=2;i
Loop through some numbers - for example, 2 through 100 - and check each one whether it is a prime number (write a second loop to test whether it is divisible by any number between 2 and the number minus 1). If, in this second loop, you find a factor that is greater than 1 and less than the number, it is not a prime, and you can print it out.
Simply use a for loop (i) that runs from 2 to N-1. Checking if N % i 0 then its a prime number.
Yes
sir , what is perfect no?
Any prime number has only two factors which are itself and one whereas composite numbers all have more than two factors
Enter "java -version" into a terminal. If Java is installed, it will tell you the version number. If it is not installed, it will say "command not found."
Java Development Kits are best found on the Java website. There are a number of programmes that can be downloaded. It is also possible to get Java Development Kit downloads from the Oracle website.
If by system number you mean the version number of the Java language on the client computer, you can useSystem.getProperty("java.version"); .Or, if you want the Java virtual machine version number you can use System.getProperty("java.vm.version"); .Finally, if you want the version number of the operating system, you can use System.getProperty("os.version"); .
Math.sqrt(number) function is used to find the square root of a number.. try it
You can use the Math.sqrt() method.