You'll need 3 variables for this, here's a pseudo code for swapping values of 2 variables.
ALGORITHM SWAP
var1 = 10
var2 = 20
temp = 0
temp = var1 "temp = 10"
var1 = var2 "var1 = 20, originally 10"
var2 = temp "var2 = 10, originally 20"
END SWAP
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Use list assignment i.e. for two variables $a, $b: ($a,$b) = ($b,$a)
#include<stdio.h> void main() { int a=2,b=4; printf("Program for swapping two numbers "); printf("Numbers before swapping"); printf("a=%d and b=%d",a,b); a=((a+b)-(b=a)); printf("Numbers after swapping"); printf("a=%d and b=%d",a,b); getch(); }
void swap (int* a, int* b) { if (!a !b) return; // can't swap a pointer to null *a^=*b^=*a^=*b; }
The only way to swap two values using call by value semantics is to pass pointer variables by value. A pointer is a variable that stores an address. Passing a pointer by value copies the address, the value of the pointer, not the pointer itself. By passing the addresses of the two values to be swapped, you are effectively passing those values by reference. Both C and C++ use pass by value semantics by default, however C++ also has a reference data type to support native pass by reference semantics. By contrast, Java uses pass by reference semantics by default. In C, to swap two variables using pass by value: void swap (int* p, int* q) { int t = *p; *p = *q; *q = t; } In C++, to swap two variables using pass by reference: void swap (int& p, int& q) { std::swap (p, q); } Note that C++ is more efficient because std::swap uses move semantics; there is no temporary variable required to move variables. With copy semantics, a temporary is required. However, with primitive data types, there is a way to swap values without using a temporary, using a chain of exclusive-or assignments: void swap (int* p, int* q) { *p^=*q^=*p^=*q; }
#include<iostream> void swap(int* x, int* x){ (*x)^=(*y)^=(*x)^=(*y); } int main() { int a, b; a=10; b=20; std::cout<<"Before swap: a="<<a<<", b="<<b<<std::endl; swap(&a,&b); std::cout<<"After swap: a="<<a<<", b="<<b<<std::endl; return(0); }