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How do you write a C program to convert a binary value to its octal equivalent?
To convert from binary to octal, bitwise AND the binary value with 0x8 (00000111 in binary) and push the value onto a stack. Right-shift (>>) the binary value by 3 bits and repeat until the binary value is zero. Pop the stack to build the left-to-right digits of the octal value. Using 10110100 as an example: 10110100 & 00000111 = 00000100 10110100 >> 3 = 00010110 00010110 & 00000111 = 00000110 00010110 >> 3 = 00000010 00000010 & 00000111 = 00000010 00000010 >> 3 = 00000000 Popping the values in order reveals 00000010, 00000110 and 00000100 (decimal 2, 6 and 4 respectively). Thus 10110100 binary is 0264 octal.
How convert octal to binary?
If necessary, pad the value with zeroes so the number of bits is an exact multiple of 3. Then divide the binary value into groups of 3 bits. Convert each group to its corresponding octal digit as follows: Bin = Oct 000 = 0 001 = 1 010 = 2 011 = 3 100 = 4 101 = 5 110 = 6 111 = 7 Example 1: 16-bit value: 1011101101100011 3-bit groupings: (00)1 011 101 101 100 011 Octal digits: 1 3 5 4 3 Octal value: 13543 Example 2: 24-bit value: 010111011010010101011010 3-bit groupings: 010 111 011 010 010 101 011 010 Octal digits: 2 7 3 2 2 5 3 2 Octal value: 27322532
Conversion of binary to octal?
Binary is a base 2 number system, while octal is base 8. This happens to make conversion between binary and octal fairly trivial, although more complex than conversion to hexadecimal. To convert to octal from binary, take each three bits, starting from the least significant bit, and convert them to their octal equivalent. Examples: 25510 = 111111112 = 11 111 111 = 3778 17410 = 101011102 = 10 101 110 = 2568 You can repeat this process for as many bits as you need. A 24-bit number should translate into 8 octal numbers, for reference.
What are the values of each bit contributing to the value of the number in octal number system?
Each octal digit is represented exactly by 3 bits: 0 = 000 1 = 001 2 = 010 3 = 011 4 = 100 5 = 101 6 = 110 7 = 111 Using the normal binary representation of the number. With a string of octal digits, each digit is the next 3 bits, for example the octal number 04751 is: 04751 = 000 100 111 101 001 in binary The spaces are for ease of reading, showing each octal digit in binary; without any spacing it becomes: 000100111101001 By changing the spacing to: 000 1001 1110 1001 means it can be easily read in hexadecimal as 0x09e9.
How do you convert octal digits into three binary digits?
C++ does not support octal encoding within source code (only decimal and hexadecimal are supported), so the octal must be represented with a string. The binary output must also be a string. Every octal digit represents three bits of binary, thus the binary output string will always be three times the length of the octal input string. The loop will begin with the octal character at index 0 and work through each character from left to right. On each iteration, the binary output string will be appended with a 3-character string, as follows: octal = binary "0" = "000" "1" = "001" "2" = "010" "3" = "011" "4" = "100" "5" = "101" "6" = "110" "7" = "111" Thus octal input "437" will begin with the "4" producing an output of "100". On the next iteration, "3" will append "011" to produce "100011". On the final iteration, "7" will append "111" to produce "100011111".
