0
public class Test {
public static void main(String[] args){
for(int i = 0; i<100; i++){
if(i%2 == 0){
System.out.println(i);
}
}
}
}
OR
public class Test {
public static void main(String[] args){
for(int i = 2; i<100;i+=2){
System.out.println(i);
}
}
}
public class forloop {
public static void main(String args[])
{
for(int i=50;i<=80;i++)
{
if(i%2==0)
{
System.out.println(i);
}
}
}
}
// finds this sum in range (1, 100]
int sum = 0;
for(int i = 2; i < 101; i+=2) {
System.out.println("Adding : " + i);
sum += i;
}
System.out.println("Sum : " + sum);
Use a for loop, and increment two at a time. Something like this:
sum = 0;
for (i = 1, i <= 100, i += 2)
sum += i;
Explanation: "i" starts at 1, the loop continues running (and adding to the sum) while i is less than or equal to 100, and i is incremented two at a time.
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What Program that will display the even numbers in data structures and algorithms?
JAVA
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Write a java script program to print first ten odd natural numbers in C?
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look at the print
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System.out.println("2, 3, 5, 7"); There are so few you dont need to calculate it
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System.err is much like System.out, except instead of going to standard output, it returns a stream to standard error. According to the Java API, you should use this to print out error messages directly to the user even if you have redirected System.out to print to a file or other stream.
