n*(n+1)
The sum of the first 20 even numbers... is 110
You cannot. There are infinitely many even numbers and their sum is not convergent.
there isn't a formula for it.you need to calculate it by your own.
You can use the formula for the sum of an arithmetic series to calculate that quickly. (Of course, you can also type the numbers into Excel, and get the sum - but that doesn't scale well - e.g., it won't work well if you are then asked, for instance, to get the sum of the first million even numbers.)
n*(n+1)
The sum of the first 20 even numbers... is 110
The sum of the first 10 even numbers is 110.
You cannot. There are infinitely many even numbers and their sum is not convergent.
To find the average of n numbers, take the sum of the numbers and divide by n.
no
there isn't a formula for it.you need to calculate it by your own.
You can use the formula for the sum of an arithmetic series to calculate that quickly. (Of course, you can also type the numbers into Excel, and get the sum - but that doesn't scale well - e.g., it won't work well if you are then asked, for instance, to get the sum of the first million even numbers.)
The sum of two evens is even so the sum of any number of evens is even. It is, therefore, impossible for the sum of three even numbers, whether or not consecutive, to be 57, which is an odd number.
of all the things i got is 2550
Sum = n/2[2Xa1+(n-1)d] where n is last number, a1 is the first number & d is the common difference between the numbers, here d=2 for the even /odd numbers. Sum = n/2 [2Xa1+(n-1)2]
The numbers are 32, 34, and 36.